individuPlan and Solvestances: R₁ = R₂ = R3 = 15 2What unknown are you trying to calculate?current=I=?What equationà can you use to find the unknown?Ohm's law: V = IRFor a parallel circuit, V = IR where Reg is the equivalent resistance.Rearranging the equation gives you I ==First, find the equivalent resistance Req150+15+15=01ReΩΩ=52ReqΩVReqThen substitute for V and R to solve for I.48 V1= 5Ω==== 9.6 A3. Look Back and CheckIs your answer reasonable?Yes, a current of 9.6 A is reasonable, and the units arereasonable.Math PracticeOn a separate sheet of paper, solve the following problems.Vor A, which is1. Calculate the current in a 9-V battery that powers three 6-2 resistorsparallel.Copyright Savvas Learning Company LLC. All Rights ReservedConceptual Physics Reading and Study Workbook.Chapter 35

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Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter29: Direct Current (dc) Circuits

Section29.5: Resistors In Parallel

Problem 29.7CE

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For the circuit shown in Figure P28.55. the ideal voltmeter reads 6.00 V and the ideal ammeter reads 3.00-k. Find (a) the value of K, (b) the emf of the battery, and (c) the voltage across the 3.00-kft resistor.
(a) When the switch S in the circuit of Figure P28.14 is closed, will the equivalent resistance between points a and b increase or decrease? State your reasoning. (b) Assume the equivalent resistance drops by 50.0% when the switch is closed. Determine the value of R.
The power dissipated in a resistor is given by P = V2/R, which means power decreases if resistance increases. Yet this power is also given by P = I2R, which means power increases if resistance increases. Explain why there is no contradiction here.
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