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Initial (M) Change (M) Equilibrium (M) 1₂(g) + Br₂(g) 14 2 IBr(g)

Initial (M) Change (M) Equilibrium (M) 1₂(g) + Br₂(g) 14 2 IBr(g)

Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.81P
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Predict the equilibrium concentration of IBr in the reaction described below (for which Kc = 280 at the reaction temperature) by constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. NEXT > In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach equilibrium. Fill in the ICE table with the appropriate value for each involved species to determine the partial pressures of all reactants and products. Where applicable, use the x variables to represent any unknown change in concentration. Initial (M) Change (M) Equilibrium (M) 0.400 + x 0 0.400 + 2x 1 12(g) + Br₂(g) = 2 IBr(g) 1₂(g) 0.400 0.400 - x 0.133 0.400-2r 2 + +X 0.133 + x Br₂(g) +2x 0.133 + 2x 3 -X 0.133 - x 2 IBr(g) RESET -2x 0.133 - 2x
Transcribed Image Text:Predict the equilibrium concentration of IBr in the reaction described below (for which Kc = 280 at the reaction temperature) by constructing an ICE table, writing an equilibrium expression for Kc, and solving for the equilibrium concentration. Complete Parts 1-3 before submitting your answer. NEXT > In a 3.0 L container at high temperature, 0.400 mol of IBr is allowed to reach equilibrium. Fill in the ICE table with the appropriate value for each involved species to determine the partial pressures of all reactants and products. Where applicable, use the x variables to represent any unknown change in concentration. Initial (M) Change (M) Equilibrium (M) 0.400 + x 0 0.400 + 2x 1 12(g) + Br₂(g) = 2 IBr(g) 1₂(g) 0.400 0.400 - x 0.133 0.400-2r 2 + +X 0.133 + x Br₂(g) +2x 0.133 + 2x 3 -X 0.133 - x 2 IBr(g) RESET -2x 0.133 - 2x
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