Initially, a warehouse worker pushes a 55 [N] box on a flat, rough, horizontal surface just enough so that the box moves with a constant velocity of 4.2 [m/s]. However, he gets tired and suddenly stops pushing the box. With the coefficient of kinetic friction between the box and the surface equal to 0.45, how long does it take for the box to stop? A. 0.95 [s] B. 2.1 [s] C. 4.4 [s] D. 9.3 [s
Initially, a warehouse worker pushes a 55 [N] box on a flat, rough, horizontal surface just enough so that the box moves with a constant velocity of 4.2 [m/s]. However, he gets tired and suddenly stops pushing the box. With the coefficient of kinetic friction between the box and the surface equal to 0.45, how long does it take for the box to stop? A. 0.95 [s] B. 2.1 [s] C. 4.4 [s] D. 9.3 [s
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
Section: Chapter Questions
Problem 68PQ
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Initially, a warehouse worker pushes a 55 [N] box on a flat, rough, horizontal surface just enough so that the box moves with a constant velocity of 4.2 [m/s].
However, he gets tired and suddenly stops pushing the box. With the coefficient of kinetic
friction between the box and the surface equal to 0.45, how long does it take for the box to
stop?
A. 0.95 [s]
B. 2.1 [s]
C. 4.4 [s]
D. 9.3 [s
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"from
vf=v0+att=vf-v0a=(0-4.2) m/s-4.41 m/s2=0.95 st=0.95 s
conclusion:
answer is option A which is 0.95 s"
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