Insert data in file customer.sal into table customer
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What is the correct command to insert data in a file into a table? I am using MySQL 8.0 Command-line Client.
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- Write the SQL code to delete the row for William Smithfield, who was hired on June 22, 2004, and whose job code is 500. (Hint: Use logical operators to include all of the information given in this problem.)Write the two SQL command sequences required to: a.Create a temporary table named TEMP_1 whose structure is composed of the EMP_2 attributes EMP_NUM and EMP_PCT. b.Copy the matching EMP_2 values into the TEMP_1 table.An EMPLOYEES table was added to the JustLee Books database to track employee information. Display a list of each employee’s name, job title, and manager’s name. Use column aliases to clearly identify employee and manager name values. Include all employees in the list and sort by manager name.
- Write the SQL code that will restore the data to its original status: that is, the table should contain the data that existed before you made the changes in Problems 5 and 6.create table patients ( patient_id VARCHAR(255),name VARCHAR(255),insurance DECIMAL(15,2),date_admitted DATE,date_checked_out DATE,PRIMARY KEY(patient_id));INSERT INTO patients (ID , name , insurance , date_admitted , date_checked_out) values (2 , 'Ali' , '22.2' , '2/1/2020' , '3/1/2020')SELECT * FROM table patients create table doctor (doctor_id VARCHAR(255),name VARCHAR(255),specialization VARCHAR(255),PRIMARY KEY (doctor_id) ); create table test (test_id VARCHAR(255),test_name VARCHAR(255),test_date DATE,test_time TIME,result VARCHAR(255),PRIMARY KEY(test_id)); create table doctor_patient( patient_id VARCHAR(255), doctor_id VARCHAR(255),PRIMARY KEY(patient_id),FOREIGN KEY(doctor_id) REFERENCES doctor(doctor_id) ); create table test_log (test_log_id varchar(255),patient_id VARCHAR(255),test_id VARCHAR(255),doctor_id VARCHAR(255),comments VARCHAR(255),PRIMARY KEY(test_log_id),FOREIGN KEY(test_id) REFERENCES test(test_id),FOREIGN KEY(patient_id) REFERENCES…create table patients ( patient_id VARCHAR(255),name VARCHAR(255),insurance DECIMAL(15,2),date_admitted DATE,date_checked_out DATE,PRIMARY KEY(patient_id));INSERT INTO patients (ID , name , insurance , date_admitted , date_checked_out) values (2 , 'Ali' , '22.2' , '2/1/2020' , '3/1/2020')SELECT * FROM table patients create table doctor (doctor_id VARCHAR(255),name VARCHAR(255),specialization VARCHAR(255),PRIMARY KEY (doctor_id) ); create table test (test_id VARCHAR(255),test_name VARCHAR(255),test_date DATE,test_time TIME,result VARCHAR(255),PRIMARY KEY(test_id)); create table doctor_patient( patient_id VARCHAR(255), doctor_id VARCHAR(255),PRIMARY KEY(patient_id),FOREIGN KEY(doctor_id) REFERENCES doctor(doctor_id) ); create table test_log (test_log_id varchar(255),patient_id VARCHAR(255),test_id VARCHAR(255),doctor_id VARCHAR(255),comments VARCHAR(255),PRIMARY KEY(test_log_id),FOREIGN KEY(test_id) REFERENCES test(test_id),FOREIGN KEY(patient_id) REFERENCES…
- SQL Table: CREATE TABLE employees ( employee_id INT PRIMARY KEY, first_name VARCHAR(255), last_name VARCHAR(255), email VARCHAR(255) UNIQUE, phone_number VARCHAR(255), hire_date DATE, job_id VARCHAR(255), salary DECIMAL(10,2), commission_pct DECIMAL(5,2), manager_id INT, department_id INT, FOREIGN KEY (manager_id) REFERENCES employees(employee_id), FOREIGN KEY (department_id) REFERENCES departments(department_id)); CREATE TABLE departments ( department_id INT PRIMARY KEY, department_name VARCHAR(255), manager_id INT, FOREIGN KEY (manager_id) REFERENCES employees(employee_id)); INSERT INTO employees (employee_id, first_name, last_name, email, phone_number, hire_date, job_id, salary, commission_pct, manager_id, department_id)VALUES (1, 'John', 'Doe', 'john.doe@example.com', '555-555-5555', '2022-01-01', 'IT_PROG', 8000, 0.2, 3, 10), (2, 'Jane', 'Smith', 'jane.smith@example.com', '555-555-5556', '2022-02-01', 'IT_PROG', 9000,…create tables appointments having columns appointment id as primary key, appointment time, appointment date, doctor id doctors having doctor id as primary key, doctor name providers having provider id as primary key, provider first name, last name, username, password, office code. Now create a provider first name as Lilly , Last name as Brooks, username as Lily_777, password as Brooks_666. Validate on the database also show me the appointments with Dr.Alex at 10.30A.Ma. Normalize the Bank Accounts Table to 1NF by increasing the records in the existing table. b. Normalize the Bank Accounts Table to 1NF by creating a new separate table in addition to the existing table.
- SQL: Start with the Employee table used in Lab 4. CREATE TABLE Employee ( EMPLOYEE_ID INT NOT NULL, FIRST_NAME CHAR(20), LAST_NAME CHAR(20), JOB_LEVEL INT, SALARY BIGINT, COMMISSION_PCT INT, CONSTRAINT PKEmployeeID PRIMARY KEY (EMPLOYEE_ID) ); INSERT INTO Employee VALUES (100,'Steven','King',1,50000,10), (101,'Neena','Kochhar',1,50000,10), (102,'Lex','De Haan',2,60000 ,15), (103,'Alexander','Hunold',2,60000,15), (104,'Bruce','Ernst',3,70000,25), (105,'Johann','Ernst',4,75000,30); Create another table. CREATE TABLE NumEmployeesByLastName ( LastName CHAR(20), NumEmployees INT ); a. Write a query to initialize the NumEmployeesByLastName table by inserting one row for each last name already in the Employee table, and having the accurate count of the number of employees having that last name. Assume that there are no null values in the Employee table. After your query, if you execute the following query, you would…1. Previous laboratory sessionCREATE DATABASE myDB; USE myDB; CREATE TABLE Customers (CustomerID int NOT NULL PRIMARY KEY,FirstName varchar(20),LastName varchar(20),Email varchar(20),Gender varchar(10),Birthdate date); CREATE TABLE Products (ProductID int NOT NULL PRIMARY KEY,Description varchar(40),Quantity int,Price float,VendorID int); USE myDB;CREATE TABLE Vendors (VendorID int NOT NULL PRIMARY KEY,Name varchar(50),ContactNum varchar(50),CityAddress varchar(50)); USE myDB;ALTER TABLE ProductsADD FOREIGN KEY (VendorID) REFERENCES Vendors(VendorID);7. Write an SQL query to update a view named VP having columns (X,Y,Z) to have columns (X,Y,Z,W) from the table T.