When is a good time to use the HTTP POST method? There are more than one correct answer! O When the request is for a page that gets data from a database server O When the request can be executed multiple times without causing any problems O When the request is for a page that writes data to a database server O When executing the request multiple times may cause problems O When you don't want to include the parameters in the URL for security reasons O When you don't want users to be able to include parameters when they bookmark a page O When you need to transfer more than 4KB of data

When is a good time to use the HTTP POST method? There are more than one correct answer! O When the request is for a page that gets data from a database server O When the request can be executed multiple times without causing any problems O When the request is for a page that writes data to a database server O When executing the request multiple times may cause problems O When you don't want to include the parameters in the URL for security reasons O When you don't want users to be able to include parameters when they bookmark a page O When you need to transfer more than 4KB of data

LINUX+ AND LPIC-1 GDE.TO LINUX CERTIF.

5th Edition

ISBN:9781337569798

Author:ECKERT

Publisher:ECKERT

Chapter7: Working With The Bash Shell

Section: Chapter Questions

Problem 5DE

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write a php code to realize the respond below according to the url and parameters，assume that there already a database contain these informations URL /api/user/update Method PUT Description To update userinfo Parameters NameTypeDescriptionusernameStringusernamerequest-typeStringsignify if the request is to update userinfo or log outdataObjectuserinfo object example: { "username":"somebody", "request-type":"log-out", "data":{ "pres" } } //or { "username":"somebody", "request-type":"update-status", "data":{ "uploadAmount":1000, "downloadAmount":1000 } } Response success: { "success": True, "message":"" } failed: { "success": False, "message":"username already exists." }
There are multiple publicly accessible web and application servers in the CSM Tech group. All of your publicly available resources are served through DNS servers. Your public DNS servers, however, are being used to perform recursive lookups for clients that are not part of your business. Recursive requests from internal clients should only be handled by your public DNS servers; iterative inquiries from external sources should be handled by the servers. Are there any more ideas that you'd want to share? Is there anything else I need to know about the solution?
Hello! I need to create a new Order with an API but I can't get it to work. My code so far is: //POST (create a new record (table)) http:API, (with additional body elements, OUCU=****, password=******, client_id=1. latitude=89, longitude=-20). function orderCreated() { let data = {oucu:"xxxxxxx",password:"xxxxxxx",client_id: 1,latitude:89,longitude:-20};var formBody = [];for (var property in data) {var encodedKey = encodeURIComponent(property);var encodedValue = encodeURIComponent(data[property]);formBody.push(encodedKey + "=" + encodedValue);}formBody = formBody.join("&"); fetch('httpAPI)', {method: 'POST',headers: {'Content-Type': 'application/x-www-form-urlencoded;charset=UTF-8'},body: formBody})}; So, it must retur: {"status" : "success","data" :[{"id":"****","client_id":"***","date":*************","latitude":"****","longitude":"-******"}]}
Rewrite the code so it looks different but has the same output <?php $cookie_name = "user";if(!isset($_COOKIE[$cookie_name])){ echo "please login in first!"; exit();} else { echo "logout"; include 'dbconfig.php'; $conn = new mysqli($hostname, $username, $password, $dbname) or die($conn->connect_error); $facultyQuery = "select Name, Fid from TECH3740.Faculty"; $roomQuery = "Select CONCAT(Building,Number) as BuR, size from TECH3740.Rooms"; $facultyResult = mysqli_query($conn, $facultyQuery); $roomResult = mysqli_query($conn, $roomQuery); $rooms = mysqli_num_rows($roomResult); echo " "; echo "Add a course"; echo "Course ID: (ex: CPS1231)"; echo "Course Name:"; echo "Term: Spring "; echo "Summer "; echo "Fall"; echo "Enrollment: (# of registered students)"; echo "Select a faculty: Select a faculty"; echo ""; while($row = mysqli_fetch_array($facultyResult)){ echo "" . $row['Name'] ; }…
Exercise 2-2 Enhance the Future Value application In this exercise, you’ll enhance the Future Value application by applying some of the skills that you’ve just learned. Test the Future Value application 1. Make sure the Apache server is running. Then, start your browser and run the application in this directory: xampp\htdocs\ex_starts\ch02_ex2 To do that, you can use the index of exercise starts that you bookmarked in exercise 1-2 or you can use this URL: http://localhost/ex_starts/ch02_ex2/ 2. Enter valid numbers in all three text boxes. For the first test run, keep these values simple like 100 for investment amount, 5 for yearly interest rate, and 10 for number of years. Then, click the Calculate button to display the results. 3. Click the Back button to return to the first page, enter invalid values in the first two text boxes, and click the Calculate button. Then, respond to the error message that’s displayed by entering valid data for the investment amount, re-entering…
main.java file import java.sql.*;public class Main { public static void main(String[] args) { try { // Connect to the library_db database, via the jdbc:mysql: channel on localhost (this PC) // Use username "otheruser", password "swordfish". Connection connection = DriverManager.getConnection( "jdbc:mysql://localhost:3306/library_db?useSSL=false", "otheruser", "swordfish" ); // Create a direct line to the database for running our queries Statement statement = connection.createStatement(); ResultSet results; int rowsAffected; // Set up finished, do some stuff: // executeQuery: runs a SELECT statement and returns the results. results = statement.executeQuery("SELECT title, qty FROM books"); // Loop over the results, printing them all. while (results.next()) {…
Create a TRIGGER in mysql. Given the table below only one person can come first but a lot of people can come second or third. Make sure on INSERT that only one person has the first place. create table RACE.Person ( Name varchar(20) not null, varchar(20) not null, position enum('first', 'second', 'third') not null );
Can you help me understand why the $type shows an error - Error: Type must be a valid integer preocess_form.php <?php $db_host = "localhost"; $db_username = "root"; $db_pass = ""; $db_name = "sc_test"; $con = mysqli_connect($db_host, $db_username, $db_pass) or die("Could not connect to MySQL"); mysqli_select_db($con, $db_name) or die("Could not select database"); if ($_SERVER["REQUEST_METHOD"] == "POST") { // Retrieve form data $sku = $_POST['sku'] ?? ''; $name = $_POST['name'] ?? ''; $price = $_POST['price'] ?? ''; $type = $_POST['type'] ?? ''; $attribute = $_POST['attribute'] ?? ''; // Validate the type value if (!is_numeric($type)) { die("Error: Type must be a valid integer"); } $type = intval($type); // Perform the database query to insert the data $query = "INSERT INTO products (sku, name, price, type, attribute) VALUES ('$sku', '$name', '$price', '$type', '$attribute')"; mysqli_query($con, $query) or die("Query failed: " . mysqli_error($con)); // Redirect to the…
Assuming you have created already created a MySQL database named "database_name" with a table named "users" that has columns for "username", "password", and "email". And that you have also created a login system that sets the "username" session variable when a user logs in.Write a simple PHP code that makes use of sessions, mysql insert, update, and delete. The code should first start with a session using session_start(). It should then connect to a MySQL database using mysqli_connect(). It inserts a new record into the users table using mysqli_query() and an SQL INSERT statement. It updates an existing record in the users table using mysqli_query() and an SQL UPDATE statement. It deletes a record from the users table using mysqli_query() and an SQL DELETE statement. It sets a session variable using $_SESSION["username"] and displays it using echo. Finally, it closes the MySQL connection using mysqli_close()
Create a php file based on this table. If the search keyword is "*", the program should display all employees in the table. <?phpinclude "dbconfig.php"; $ip = $_SERVER['REMOTE_ADDR'];echo " Your IP: $ip\n";$IPv4 = explode(".", $ip); if (($IPv4[0] == '10') || ($IPv4[0] == '131' && $IPv4[1] == '125')) { echo " You are from Kean University.";} else { echo " You are NOT from Kean University.";} $keyword = isset($_POST["keyword"]) ? $_POST["keyword"] : ''; $conn = mysqli_connect($servername, $username, $password, $dbname);if (!$conn) { die("Connection failed: " . mysqli_connect_error());} if ($keyword === '*') { $query = "SELECT * FROM EMPLOYEE"; $result = mysqli_query($conn, $query); if ($result) { $employeeCount = mysqli_num_rows($result); echo "There are $employeeCount employee(s) in the database."; if ($employeeCount > 0) { displayEmployeeTable($result); } else {…
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