INSTRUCTOR ELDER Math 100 LAB 16 Factor each of the following, factor each completely. First look to see if it is a special factoring case. Or look to factor out the greatest common factor if there is one. First rewrite each in the form of Ax2 + Dx + Ex + C and then factor by grouping. Write your answer in the blank provided. (3x+) 1. 1. Зx2 -13х — 10 2. 2. 10x2 – 17x - 20 2x-3 2x? + x – 6 (x+2)(6 4. 6x2 + 2x - 4 4. 2x2 – x – 6 6. 15x2 + 24x + 9 6. Louren erber 5. 3. 5. Factor each of the following completely. First look to see if it is a special factoring case. Or look to factor out the greatest common factor if there is one. Write your answer in the blank provided. 7. 7. 6x2 + 8x – 8 8. 20x? – 20 (hint: first factor greatest common factor) 8. 9. 9. x² – 16 (hint: special factoring case) 10. x2 - 2x - 8 10. 11. x3 – 5x2 – 9x + 45 (hint: factor by grouping) 11. 12. x*y - x³y2 – 6x2y3 (hint: first factor greatest 12. common factor)

INSTRUCTOR ELDER Math 100 LAB 16 Factor each of the following, factor each completely. First look to see if it is a special factoring case. Or look to factor out the greatest common factor if there is one. First rewrite each in the form of Ax2 + Dx + Ex + C and then factor by grouping. Write your answer in the blank provided. (3x+) 1. 1. Зx2 -13х — 10 2. 2. 10x2 – 17x - 20 2x-3 2x? + x – 6 (x+2)(6 4. 6x2 + 2x - 4 4. 2x2 – x – 6 6. 15x2 + 24x + 9 6. Louren erber 5. 3. 5. Factor each of the following completely. First look to see if it is a special factoring case. Or look to factor out the greatest common factor if there is one. Write your answer in the blank provided. 7. 7. 6x2 + 8x – 8 8. 20x? – 20 (hint: first factor greatest common factor) 8. 9. 9. x² – 16 (hint: special factoring case) 10. x2 - 2x - 8 10. 11. x3 – 5x2 – 9x + 45 (hint: factor by grouping) 11. 12. x*y - x³y2 – 6x2y3 (hint: first factor greatest 12. common factor)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter8: Polynomials

Section8.5: Using The Distributive Property

Problem 51PPS

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Similar questions

The Special Factoring Formula for the “difference of squares” is A2B2=. So, 4x225 factors as _____________.
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