Instructor-created questionWhen subjects were treated with a drug, their systolic blood pressure readings (in mm Hg) were measured before and after the drug was taken. Results are given in the table below. Assume that the paired sampledata is a simple random sample and that the differences have a distribution that is approximately normal. Using a 0.05 significance level, is there sufficient evidence to support the claim that the drug is effective inIowering systolic blood pressure?157152164148194169158159193170205143189155159163210179167177195176188179BeforeAfterIn this example, y, is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the systolic blood pressure reading before the drug was taken minus thereading after the drug was taken. What are the null and alternative hypotheses for the hypothesis test?B. H Pd

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Asked Nov 19, 2019
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Instructor-created question
When subjects were treated with a drug, their systolic blood pressure readings (in mm Hg) were measured before and after the drug was taken. Results are given in the table below. Assume that the paired sample
data is a simple random sample and that the differences have a distribution that is approximately normal. Using a 0.05 significance level, is there sufficient evidence to support the claim that the drug is effective in
Iowering systolic blood pressure?
157
152
164
148
194
169
158
159
193
170
205
143
189
155
159
163
210
179
167
177
195
176
188
179
Before
After
In this example, y, is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the systolic blood pressure reading before the drug was taken minus the
reading after the drug was taken. What are the null and alternative hypotheses for the hypothesis test?
B. H Pd <0
O A H Ha 0
O C. H Ha 0
Identify the test statistic.
(Round to two decimal places as needed.)
Identify the P-value.
(Round to three decimal places as needed.)
P-value=
evidence to support the claim that the drug is effective in lowering systolic blood pressure.
There is
5%
52
53
54
55
56
57
58
59
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Instructor-created question When subjects were treated with a drug, their systolic blood pressure readings (in mm Hg) were measured before and after the drug was taken. Results are given in the table below. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Using a 0.05 significance level, is there sufficient evidence to support the claim that the drug is effective in Iowering systolic blood pressure? 157 152 164 148 194 169 158 159 193 170 205 143 189 155 159 163 210 179 167 177 195 176 188 179 Before After In this example, y, is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the systolic blood pressure reading before the drug was taken minus the reading after the drug was taken. What are the null and alternative hypotheses for the hypothesis test? B. H Pd <0 O A H Ha 0 O C. H Ha 0 Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) P-value= evidence to support the claim that the drug is effective in lowering systolic blood pressure. There is 5% 52 53 54 55 56 57 58 59

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Expert Answer

Step 1

The hypotheses are given below:

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Null hypothesis: H = 0 Alternative hypothesis: H <0

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Step 2

Test statistic

Step-by-step procedure to obtain the p-value and test statistic using MINITAB software:

  • Choose Stat > Basic Statistics > Paired t.
  • Choose Samples in different columns.
  • In sample 1, enter the column of Before.
  • In sample 2, enter the column of After.
  • Choose Options.
  • In Confidence level, enter 95.
  • In Hypothesized difference, enter 0.
  • In Alternat...
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Paired T-Test and Cl: Before, After Descriptive Statistics Sample N Mean StDev SE Mean Before 12 181.58 19.33 5.58 After 12 164.17 12.69 3.66 Estimation for Paired Difference 95% Upper Bound for difference Mean StDev SE Mean 17.42 19.81 5.72 27.68 difference: mean of (Before - After) Test Hoi4_difference = o Null hypothesis Alternative hypothesis H:difference <0 T-Value P-Value 3.05 0.994

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