int n = 1; // global print1 (int x) { cout << x + n; plus_n () { n = n + 2; print1 (n); main() { int n; n 20; print1(5); n = 40; plus_n(); cout << n; } what is the output of main under: a. Static scoping rules 6 6 40 b. Dynamic scoping rules 25 84 40
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- IN HASKELL PROGRAMMING LANGUAGE PLEASE In case you do not know it: the game is played on a 3x3 grid that is initially empty. Two players are playing, by alternatingly making moves. A move by a player places their token (an X for player 1, an O for player 2) into a cell that was empty. We are using algebraic notations for indexing the positions in the board, with A,B,C indexing the columns and 1,2,3 the rows. Specifically, these coordinates would be used in the implementation for moves made by a human player. If the X X O Figure 1: Sample board position same token appears 3 times in any of the three columns, three rows or two main diagonals the game is over and that player wins. If the grid is filled without that happening the game is a draw. For the depicted board, we have Xs in positions C3 and A2, and an O in position B1. It would be O’s turn to make a move; a legal move would be C2, but it is not a good move, because X can force a win by responding A1. O cannot force a win, but…A binary operator is an operation that is performed on two operands. For example, addition is a binary operator that adds two operands (e.g., 2 + 4). In the provided UML diagram, all binary operators have two operands and an execute method that performs the appropriate operation on the operands. The AddOperation class should add the two operands. The SubtractOperation class should subtract the two operands. Here is an example of how a binary operator could be used: IBinaryOperator operator = new AddOperator(8, 12);System.out.println(operator.execute()); // should print 20operator.setLeftOperand(18);System.out.println(operation.execute()); // should print 30 crate a Main.java to test your codeLanguage is c++ Assignment 6 C: Minesweeper - Simplified. For many years, computers sold with the Windows operating system would contain a game called M inesweeper. The player would be presented with a grid, where they would have to click an empty part of the map. If they clicked on a hidden mine, the game would be instantly over. However, if they clicked a safe spot, a hint about nearby mines would be displayed and the player would click another spot. The goal would be to flag all the hidden mines without hitting one. (As an aside, many people did not know these rules and just clicked around randomly until they hit a mine)We will be developing a simplified version of this game. You will prompt the user for a grid size and then created a 2D array with equal width and height (C++ students: Check the Appendix for more information on how to do this). You will initialize the 2D char array with each element equallying a ‘?’ symbol. You will then randomly generate one “mine” value per…
- Java code: final static Scanner cin = new Scanner(System.in); public static void main(String[] args) { out.println("CPS 151 In-class assignment 3 by ___ your name here ___\n"); out.print("Enter n: "); int n = cin.nextInt(); long f = fib(n); out.println("\nfib(" + n + ") = " + f); out.println("\nCPS 151 In-class assignment 3 complete"); } // end main // standard fibonacci number computation using recursion static long fib(int n) { if (n < 0) terminate("Negative argument value not allowed, program ended"); if (n <= 1) return n; else return fib(n - 1) + fib (n - 2); } // end fib private static void indent(int level) { for(int Lcv = 1; Lcv <= level; Lcv++) out.print(" "); } // end indent private static void terminate(String errorMessage) { out.println(errorMessage); System.exit(1); } // end terminateidentify the following as better representing static or dynamic binding. a) an int is an int forever and ever amen b) 2/2.0 = 1.0 c) 3/2.0 -> error message d) binding is done at compile time e) binding is slower but more flexibleFor the code in java below it shows a deck of 52 cards and asks the name of the two human players and makes both players draw five cards from the deck. What I want to added into the code is for Player A to manually pick a card from his/her 5 cards and have Player B pick two cards that equal the value of Player A's card if possible. Main class code and Player class code shown below: Main class code: import java.util.ArrayList; import java.util.Scanner; import java.util.List; import java.util.Random; class Main { publicstaticvoid main(String[] args) { // card game, two players, take turns. String[] suits = {"Hearts", "Clubs", "Spades", "Diamonds"}; String[] numbers = {"A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"}; for(String oneSuit : suits){ for(String num : numbers){ System.out.println(oneSuit + " " + num); } } List<Player> listOfPlayers = new ArrayList<>(); Scanner sc = new Scanner(System.in); System.out.println("Name of Player 1");…
- 1. (Dice simulation) Java/C++ program that computes the exact probability distribution for the sum of two dice. Run experiments to validate this calculation simulating N dice throws, keeping track of the frequencies of occurrence of each value when you compute the sum of two random integers between 1 and 6. How large does N have to be before your empirical results match the exact results to three decimal places?Case Diagram and UML Class Diagram for this java code : (Below the code give some constructive critiques about the UML class diagram)…. Thanks import java.util.*; public class BeverlyBreads{public static void main(String[] args){Scanner input = new Scanner(System.in); //Array for breads String[] breads = new String[5]; //Bread choices breads[0] = "White Bread"; breads[1] = "Wheat Bread"; breads[2] = "Rye Bread"; breads[3] = "Pumpernickel Bread"; breads[4] = "Baguette"; //Prices for the breads double[] prices = new double[5]; prices[0] = 2.99; prices[1] = 3.49; prices[2] = 3.99; prices[3] = 4.49; prices[4] = 4.99; //Customer's Name System.out.println("Enter customer's name: "); String name = input.nextLine(); //Customer's Phone Number System.out.println("Enter customer's phone number: "); String phoneNumber = input.nextLine(); //Bread Selection System.out.println("Which bread would you like to order?"); for(int i = 0; i < breads.length; i++) { System.out.println(breads[i] + "…THIS NEEDS TO BE DONE IN C#! NOT JAVA! NOT C++, NOT PYTHON! PLEASE WRITE THIS IN C#! Take the following class: class Pokemon { string Name; string Type; int Health; } Override the ToString method so that it it outputs the Pokemon's heath. Example: Let's say we have a Pikachu named Sparky and it had 200 health. When we called ToString, we would get the following string: Rex: Pikachu (200)
- Write a Java program DecimalToBinary that implements the static method decimalToBinary() which converts decimal number N to its binary representation. Note: You are not allowed to use a built-in subroutine like Integer.toBinaryString(). (Consider the structure below shown in the picture. It must have the same structure)Change Java code below so that it outputs a 9x9 board and not a 3x3 board. import java.util.*; public class Tic_Tac_Toe{ static String[] board;static String turn;static String checkWinner(){for (int a = 0; a < 8; a++) {String line = null; switch (a) {case 0:line = board[0] + board[1] + board[2];break;case 1:line = board[3] + board[4] + board[5];break;case 2:line = board[6] + board[7] + board[8];break;case 3:line = board[0] + board[3] + board[6];break;case 4:line = board[1] + board[4] + board[7];break;case 5:line = board[2] + board[5] + board[8];break;case 6:line = board[0] + board[4] + board[8];break;case 7:line = board[2] + board[4] + board[6];break;}//For X winnerif (line.equals("XXX")) {return "X";} // For O winnerelse if (line.equals("OOO")) {return "O";}} for (int a = 0; a < 9; a++) {if (Arrays.asList(board).contains(String.valueOf(a + 1))) {break;}else if (a == 8) {return "draw";}} // To enter the X Or O at the exact place on board.System.out.println(turn + "'s turn; enter…(Numerical) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters to 0, and then generate a large number of pseudorandom integers between 0 and 9. Each time a 0 occurs, increment the variable you have designated as the zero counter; when a 1 occurs, increment the counter variable that’s keeping count of the 1s that occur; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of the time they occurred.