Integrating Factor by Inspection: 1. (2y – 3x)dx + xdy = 0 2. (x – y²)dx + 2xydy = 0 %3D %3D
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- Find the constant of proportionality. z is directly proportional to the sum of x and y. If x=2 and y=5, then z=28.Solve by integrating factors found by inspection: y (x2 - y2 + 1)dx - x (x2 - y2 - 1) dy = 0Pls solve using Integrating Factors Found by Inspection y ( x^3 e^xy - y)dx + x(y + x^3 e^xy)dy = 0
- y(8x-9y)dx+2x(x-3y)dy Determination of integrating factor by inspectionSolve using Integrating Factor by Inspection. Show Complete Solution. y^2 ( 1 − x^2 ) dx + x ( x^2y + 2x + y ) dy=0 Ans: x^2 y + x + y = cxy^2DE with Integrating Factor Found by Inspection solve (3x2y3 - x3 + 1)dx + (3x3y2 + y2)dy = 0
- Solve using Integrating Factor by Inspection. Show Complete Solution. (x^3+xy^2-y)dx+(y^3+x^2y+x)dy=0 Ans: 2arctan(y/x)=c-x^2-y^2B2. Find the integrating factor by inspection then solve. y(y2 + 1)dx + x(y2 - 1)dy = 0Integrating Factor by Inspection a.) y(x²−y² + 1)dx− x(x²−y²−1)dy= 0 b.) y²(xdx + ydy) + (x² + y²)(ydx−xdy) = 0