Interval for One Sample Continuous OutcomeAn investigator wants to estimate the mean birth weight of infants bornfull term to mothers who are 19 years of age or youngerThe mean birth weight of infants born full term to mothers 20 years ofage and older is 351Qg with a standard deviation of 385gA. How many women 19 years of age or younger must be enrolled in the study toensure that a 95% confidence interval estimate of the mean birth weight of their196infants has a margin of error not exceeding 100g?B. How many do you need if 5% deliver pre-term?ONES & BARTLETT LEARNING2011 Jones & Bartlett Learning, LLC

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Asked Oct 28, 2019
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Problem 1 

Interval for One Sample Continuous Outcome
An investigator wants to estimate the mean birth weight of infants born
full term to mothers who are 19 years of age or younger
The mean birth weight of infants born full term to mothers 20 years of
age and older is 351Qg with a standard deviation of 385g
A. How many women 19 years of age or younger must be enrolled in the study to
ensure that a 95% confidence interval estimate of the mean birth weight of their
196
infants has a margin of error not exceeding 100g?
B. How many do you need if 5% deliver pre-term?
ONES & BARTLETT LEARNING
2011 Jones & Bartlett Learning, LLC
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Interval for One Sample Continuous Outcome An investigator wants to estimate the mean birth weight of infants born full term to mothers who are 19 years of age or younger The mean birth weight of infants born full term to mothers 20 years of age and older is 351Qg with a standard deviation of 385g A. How many women 19 years of age or younger must be enrolled in the study to ensure that a 95% confidence interval estimate of the mean birth weight of their 196 infants has a margin of error not exceeding 100g? B. How many do you need if 5% deliver pre-term? ONES & BARTLETT LEARNING 2011 Jones & Bartlett Learning, LLC

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Expert Answer

Step 1

Given information:

Mean, µ=3,510

Standard deviation, σ=385

Step 2

Computation of number of women 19 years of age or younger enrolled in the study:

Using the EXCEL formula, “=NORM.S.INV(C5)”, the value of z for 95% confidence level is 1.96.

To ensure that the 95% confidence interval estimate...

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2 ZO E 1.96 x385 100 =56.94 57

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