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Investigation 1: Similarity Criteria Proof of SSS Similarity Theorem AB BC AC XY YZ XZ Prove: ABC XYZ Given: Let D be a point on AB such that DB = XY There exists DE such that DE AC ZA ZBDE and ZCZBED ABCDBE AB=BC=AC BE AB=BC=AC DE AB=BC=AC Пр 7 XZ ВС BEC and 4 = 4 and AB > XY BC YZ = BC BE and AC XZ = AC DE YZ = BE and XZ = DE D Given a line and a point not on the line, there is exactly one line that passes through the point and is parallel to the given line. c SSS~ AA~ Cross multiplication/multiplication property SSS Note: There is 1 extra tile that does not belong in the proof Arrange the tiles in the correct order to complete the proof. Corresponding angle theorem Division property Corresponding sides of similar triangles are proportional Transitive Property

Investigation 1: Similarity Criteria Proof of SSS Similarity Theorem AB BC AC XY YZ XZ Prove: ABC XYZ Given: Let D be a point on AB such that DB = XY There exists DE such that DE AC ZA ZBDE and ZCZBED ABCDBE AB=BC=AC BE AB=BC=AC DE AB=BC=AC Пр 7 XZ ВС BEC and 4 = 4 and AB > XY BC YZ = BC BE and AC XZ = AC DE YZ = BE and XZ = DE D Given a line and a point not on the line, there is exactly one line that passes through the point and is parallel to the given line. c SSS~ AA~ Cross multiplication/multiplication property SSS Note: There is 1 extra tile that does not belong in the proof Arrange the tiles in the correct order to complete the proof. Corresponding angle theorem Division property Corresponding sides of similar triangles are proportional Transitive Property

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.3: The Addition And Subtraction Formulas
Problem 76E
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DISCOVery MATH EDUCATION Investigation 1: Similarity Criteria Proof of SSS~ Similarity Theorem AB BC AC XY YZ XZ Given: Prove: ABC XYZ Let D be a point on AB such that DB = XY There exists DE such that DE AC ZA = ZBDE and ZC = ZBED ABCDBE AB BC AC DB = BE = DE AB XB = BC = AC YZ AB = DB = BC = AC TECHBOOK BE AC DE BC = BC and C= AC XZ YZ = BE and XZ = DE BC YZ = BC BE and AC XZ = AC DE DBE = XYZ and AB > XY ABC XYZ If a triangle is similar DELL Given a line and a point not on the line, there is exactly one line that passes through the point and is parallel to the given line. E SSS~ AA~ Cross multiplication/multiplication property SSS Note: There is 1 extra tile that does not belong in the proof Z Arrange the tiles in the correct order to complete the proof. Corresponding angle theorem Division property Given Corresponding sides of similar triangles are proportional Transitive Property Substitution Property
Transcribed Image Text:DISCOVery MATH EDUCATION Investigation 1: Similarity Criteria Proof of SSS~ Similarity Theorem AB BC AC XY YZ XZ Given: Prove: ABC XYZ Let D be a point on AB such that DB = XY There exists DE such that DE AC ZA = ZBDE and ZC = ZBED ABCDBE AB BC AC DB = BE = DE AB XB = BC = AC YZ AB = DB = BC = AC TECHBOOK BE AC DE BC = BC and C= AC XZ YZ = BE and XZ = DE BC YZ = BC BE and AC XZ = AC DE DBE = XYZ and AB > XY ABC XYZ If a triangle is similar DELL Given a line and a point not on the line, there is exactly one line that passes through the point and is parallel to the given line. E SSS~ AA~ Cross multiplication/multiplication property SSS Note: There is 1 extra tile that does not belong in the proof Z Arrange the tiles in the correct order to complete the proof. Corresponding angle theorem Division property Given Corresponding sides of similar triangles are proportional Transitive Property Substitution Property
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