Portfolio V (1-5) Directions: Match the following terms in column A to the description that matches them in column B.Column AColumn B1. FiltrationA. Technique of separating a mixture by passing it insolution or suspension or as a vapor through amedium in which the components move atdifferent rates2. ChromatographyB. Process of separating components of mixtures byusing magnets to attract magnetic materials.C. the technique which involves the application ofcentrifugal force to separate particles from asolution.3. Evaporation4. Magnetic separationD. Process for the separation of mixtures ofimmiscible liquids or of a liquid and a solid mixturesuch as a suspensionE. Separation process that makes use of differencesin solubility of the components present in the melt orthe solution5. DecantationF. Process where the components of a liquid mixtureare vaporized and then condensed and isolated.G. Technique where involved solution is heated untilorganic solvent turns into gas mostly leaving behindthe solid residue.Page 11 | 12H. Separation method used to separate out puresubstances in mixtures comprised of particles someof which are large enough in size to be capturedwith a porous material.1. Used to separate a dry mixture which containssubstances of different sizes by passing it through asieve.J. Only useful when the particles are large enough tobe seen clearly.

irections: Match the following terms in column A to the description that matches them in column Column A Column B A. Technique of separating a mixture by passing iti solution or suspension or as a vapor through a medium in which the components move at different rates 1. Filtration 2. Chromatography B. Process of separating components of mixtures b using magnets to attract magnetic materials. C. the technique which involves the application c centrifugal force to separate particles from solution. 3. Evaporation D. Process for the separation of mixtures c immiscible liquids or of a liquid and a solid mixtur such as a suspension 4. Magnetic separation E. Separation process that makes use of difference in solubility of the components present in the melt o the solution 5. Decantation F. Process where the components of a liquid mixtur are vaporized and then condensed and isolated. G. Technique where involved solution is heated un organic solvent turns into gas mostly leaving behin the solid residue.

irections: Match the following terms in column A to the description that matches them in column Column A Column B A. Technique of separating a mixture by passing iti solution or suspension or as a vapor through a medium in which the components move at different rates 1. Filtration 2. Chromatography B. Process of separating components of mixtures b using magnets to attract magnetic materials. C. the technique which involves the application c centrifugal force to separate particles from solution. 3. Evaporation D. Process for the separation of mixtures c immiscible liquids or of a liquid and a solid mixtur such as a suspension 4. Magnetic separation E. Separation process that makes use of difference in solubility of the components present in the melt o the solution 5. Decantation F. Process where the components of a liquid mixtur are vaporized and then condensed and isolated. G. Technique where involved solution is heated un organic solvent turns into gas mostly leaving behin the solid residue.

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter14: Chromatography

Section: Chapter Questions

Problem 9P

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Which statements are NOT true regarding chromatography? I The stationary phase is typically a liquid bonded to the inside surface of a capillary or the surface of solid packed in the column.II The mobile phase entering the column is the eluate.III Mobile phase is the solvent (gas or liquid) that moves through the column.IV Eluent is the process of passing mobile phase though a column.V Columns are either open tubular or packed. A. II and IV B. I, II, and III C. I, IV, and V D. I and V E. III and V
Complete the sentence. All the following are common carrier gases from gas chromatography, EXCEPT: A. Oxygen. B. Helium. C. Carbon dioxide. D. Nitrogen. E. Argon.
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A 0.500g sample is analyzed spectrophotometrically for manganese by dissolving it in acid and transferring to a 250 mL flask and diluting to volume. Three aliquots ae analyzed by transferring 50 mL portions with a pipet to 500 mL Erlenmeyer flask and reacting with an oxidizing agent, potassium peroxydisulfate, to convert the manganese to permanganate. After reaction, these are quantitatively transferred to 250 mL volumetric flasks, diluted to volume and measured spectrophotometrically. By comparison with standards, the average concentration of the final solution is determined to be 1.25 x 10^-5M. What is the percent manganese in the sample?
Chromatography question A student properly sets up a column chromatography experiment. Although the mixture is soluble i the mobile phase, the sample appears "stuck" at the top of the column and will not elute eregardless of how much solvet is pplaied. what could bee the cause of this issue and what could teh student try to achieve a successful separation?
1. Explain the importance of using a thermometer in the simple distillation setup? 2. Enumerate the characteristics of a substance for it to be separated from the heterogeneous mixture by steam distillation? Please explain well and don't copy from google
Can paper chromatography be used to separate and identify very volatile substances? How do I prove this.
Which statement(s) are correct for gas chromatography? A) the components in a mixture can be identified from their retention time. B) the relative peak areas give the proportions of components in a mixture. C) Calibration curves are used to confirms the concentrations of components in a mixture.
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One method for the quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is area normalization. Here, complete elution of all the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction involves dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2 and 30.2, in order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78 and 0.88, respectively.
5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?