is 70% the correct answer？I am so confused ，if 70% is not the correct answer please in detail explain why not？and what is correct answer？how did you get the correct answer，show all your work please
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- Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?Two different female Drosophila were isolated, each heterozygous for the autosomally linked genes black body (b), dachs tarsus (d), and curved wings (c). These genes are in the order d–b–c, with b closer to d than to c. Shown in the following table is the genotypic arrangement for each female, along with the various gametes formed by both. Identify which categories are noncrossovers (NCO), single crossovers (SCO), and double crossovers (DCO) in each case. Then, indicate the relative frequency with which each will be produced.The following is a linkage map of chromosome 5 for three genes in tomato: (see image) The cross between the triple heterozygote (Lf J W/ lf j w) and a triple homozygous recessive produced 500 progeny. Assume that there is no interference in the Lf-W region. Give the expected number of individuals for each of the following progeny types and show complete solutions.a. with crossover in the Lf-J and J-W regionsb. with crossover in the Lf-J regionc. with crossover in the J-W regiond. without crossover in the Lf-W region
- A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type males and only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 494 w + + 394 + + ct 28 w y + 35 + y + 105 w + ct 101 w y ct 5 + + + 3In autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain. What phenotypic ratio of green to red is expected if: the Fl's are intercrossed? Show your solution. the Fl's are crossed with red plants? Show your solution.Two recessive traits in mice—droopy ears and flaky tail—arecaused by genes that are located 6 mu apart on the same chromosome.A true-breeding mouse with normal ears (De) and a flaky tail ( ft)was crossed to a true-breeding mouse with droopy ears (de) and anormal tail (Ft). The F1 offspring were then crossed to mice withdroopy ears and flaky tails. If this testcross produced 100 offspring,what is the expected outcome of phenotypes?
- In autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain. 1. What phenotypic ratio of green to red is expected if: a. the Fl's are intercrossed? Show your solution. b. the Fl's are crossed with red plants? Show your solution. c. If the G locus were 50 or more map units from the centromere, what types and proportions of gametes would the Fl be expected to produce? Derive the expected F2 phenotypic ratio.The alleles his-5 and lys-1, found in yeast, result in cells that require histidine and lysine for growth, respectively. A cross was made between two haploid yeast strains that are his-5 lys-1 and his+ lys+. 973 tetrads were analyzed, with the follow pattern: 7 tetrads with 2 his-5 lys+ spores and 2 his+ lys-1 spores 603 tetrads with 2 his-5 lys-1 spores and 2 his+ lys+ spores 363 tetrads with 1 his-5 lys-1 spore, 1 his-5 lys+ spore, 1 his+ lys-1 spores, and 1 his+ lys+ spore Compute the map distance between these two genes using the method that considered double crossovers and the one that does not. Show your work. Which give the higher value? Why? What is the frequency of single crossovers between these genes? Explain. Based on the frequency of single-crossovers, how many double crossovers would one expect? Is positive interference occurring?The alleles his-5 and lys-1, found in yeast, result in cells that require histidine and lysine for growth, respectively. A cross was made between two haploid yeast strains that are his-5 lys-1 and his+ lys+. 973 tetrads were analyzed, with the follow pattern: 7 tetrads with 2 his-5 lys+ spores and 2 his+ lys-1 spores 603 tetrads with 2 his-5 lys-1 spores and 2 his+ lys+ spores 363 tetrads with 1 his-5 lys-1 spore, 1 his-5 lys+ spore, 1 his+ lys-1 spores, and 1 his+ lys+ spore Compute the map distance between these two genes using the method that considered double crossovers and the one that does not. Which gives the higher value? Why? What is the frequency of single crossovers between these genes? Explain. Based on the frequency of single-crossovers, how many double crossovers would one expect? Is positive interference occurring?
- Two genes on chromosome 7 of corn are glossy (g) for leaf texture and ramosa (r), which determines how the ears branch. A test cross between a heterozygous plant for both loci and a doubly recessive plant produces the following progeny and genotypes Phenotype Number of corn kernels counted GR / gr 46 G r / gr 125 g r / gr 45 g R / gr 121 What is the recombination frequency (in %) for the two loci? ___A hypothetical brown frog with black spots (genotype BbSs) is test crossed with a green, unspotted frog (genotype bbss). These produce the following progeny: brown + spotted: 64 brown + unspotted: 134 green + spotted: 130 green + unspotted: 72 a. What is the genotype of the original dihybrid frog? Specify which alleles are on each chromosome of the brown frog with black spots (i.e. AB/ab or Ab/aB). b. How many map units separate the colour and spot genes? Show your calculations.An ear of corn has a total of 381 grains, including 216 Purple & Smooth, 79 Purple & Shrunken, 65 Yellow & Smooth, and 21 Yellow & Shrunken. This ear of corn was produced by a dihybrid cross (PpSs x PpSs) involving two pairs of heterozygous genes resulting in a theoretical (expected) ratio of 9:3:3:1. Use a chi square
