is defined as the mixture of different content forms such as texts, music, photos or images, interactive content, animations or videos. А. User Experience В. Rich Content C. Multimedia D. Infographic
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- Use the format SEEMMMM. All digits are decimal. The exponent is stored excess-50. The implied decimal point is at the beginning of the mantissa. The sign is 1 for a positive number, 7 for a negative number. Hint: Note carefully the number of digits in the mantissa! a. Convert the decimal number 28643 to floating point.b. What is the range of numbers that can be stored in this format? c. What is the floating-point representation for: −28569? d. What is the floating-point representation for 0.0000019557?4. a. Please translate with a three-address statement, the following expression:n = f((x+2), y) – 5;5. Declare a 32-bit signed integer variable and initialize it with the value 234 (base 10). In memory, what are the hexadecimal values shown?
- 10. Fill in the following addition table for base 3.+ 0 1 201211. Identify the following statements as TRUE OR FALSE. a) BCD stands for Binary Coded Decimal and encodes each digit of a decimal number to an 8-bit binary form. b) Unicode is a 16-bit code, occupying twice the disk space for text as ASCII or EBCDIC would require. c) A signed-magnitude integer representation includes more negative numbers than it does positive ones. d) A byte is 8 bits, but a word may vary in size (16-bits, 32-bits, etc.) from one architecture to another. e)The largest value that a 60-bit unsigned binary integer can represent is (260-1). f) A 2's complement integer representation includes more negative numbers than it does positive ones.this is a C++ programs and convert the programinto a complete assembly program using MIPS. calculate the total cost using MIPS. #include <iostream> int main() { int adults; int children; double totaladults; double totalchildren; double total; char option; std::cout << "Welcome to Happy Tour Agency" << std::endl; std::cout << "We have a special rate for 3 days and 2 nights at Langkawi Island,\n" "Pangkor Island, and Tioman Island" << std::endl; std::cout << "Full cost for 3 days for an adult are as follows: " << std::endl; std::cout << "Destination Flight(2 ways) Hotel(3 days)\n" "Langkawi RM 120.00 RM 260.00\n" "Pangkor RM 90.00 RM 330.00\n" "Tioman RM 150.00 RM 390.00" << std::endl; std::cout << "50% discount for each child" << std::endl; std::cout << std::endl; std::cout << "Please enter the number of adults that are going: "; std::cin…A list of positive and negative numbers are in A2 through A400, and the square root of the absolute value is needed for each cell. Which function typed into B2 and copied through B400 will provide this information? a. =A2^(1/2) b. =SQRT(A2) c. =SQRT(ABS(A$2)) d. =SQRT(ABS(A2))
- the odd numbers are the numbers in the sequence 1,3,5,7,9, .... Define the sequence of S - numbers as follows: the first S - number is 1 The second S - number is the sum of the first S - number and the second odd number the third s - number is the sum of the second S- number and the third odd number. the fourth S- number is the sum of the third S- number and the fourth odd number, etc..,... compute the first seven S- numbers. make a note of any patterns you notice. enter the first seven S- numbers as a comma - seperated list: first seven S- numbers = ________________(Limitations of Floating-Point Numbers for Monetary Amounts) Section 4.6 cautionedabout using floating-point values for monetary calculations. Try this experiment: Create a floatvariable with the value 1000000.00. Next add to that variable the literal float value 0.12f. Displaythe result using printf and the conversion specifier "%.2f". What do you get?Please answer in C++ Your country is at war and your enemies are using a secret code to communicate with one another. You have managed to intercept a message that reads as follows: :mmZ\dxZmx]Zpgy The message is obviously encrypted using the enemy's secret code. You have just learned that their encryption method is based upon the ASCII code. Appendix 3 shows the character set. Individual characters in string are encoded using this system. For example, the character "A" is encoded using the number 65, and "B" is encoded using the number 66. Your enemy's secret code takes each letter of the message and encrypts it as follows : if (orginalChar + key > 126) then encryptedChar = 32 + ((orginalChar + key) -127) else encryptedChar = (orginalChar +key) For example, if the enemy uses key = 10 then the message "Hey" would be encrypted as: Character ASCII code H 72 e 101 y…
- 1. Convert 1.375 and 0.75 to the 14-bit floating-point format of the textbook and add them up in that format, then convert your 14-bit result back to decimal and verify your computation. 2. Q2. What is the smallest 32-bit floating-point number f such that 128 + f > 128? What is the smallest 32-bit floating-point number g such that 1 + g > 1? What is the relationship between f and g? Write a short C++ or Python program to support your answer (for example, show that you checked whether there is no smaller number than your f by trying 128+f/2 == 128. 3.Explain what changes are needed to change the 4x3 memory presented on Slide 62 of Chapter 3 to a 16x6 memory.c++ How do I correct this into the correct format: The input begins with the number of locations. Each location is entered x and then y and then name. Output the name of the closest locations. Here is my code: #include <bits/stdc++.h>#include <cmath>using namespace std; //Compute the distance between two points (x1, y1) and (x2 y2)double getDistance(double x1, double y1, double x2, double y2){ return sqrt ((x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1));} struct Location{ string name; double x; double y;}; int main() { int y = 0; int locationName = 40; const int NUMBER_OF_POINTS = 5; // Each row in points represents a location Location location[NUMBER_OF_POINTS]; // make sure to enter the name of the location so like // longview 237.89 46.68 // dallas 373.62 47.0 cout << "Enter " << NUMBER_OF_POINTS << " points: "; for (int i = 0; i < NUMBER_OF_POINTS; i++) cin >> location[i].name >> location[i].x >>…Q1 \ Convert the following infix expression into postfix one: (A+B^D)/(D-F)+G PS: you have to illustrate the different steps of this conversion one by one.