Is the charge (Q) on capacitor directly proportional to potential (V) across its plates?

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter27: Capacitors And Batteries
Section27.3: Batteries
Problem 27.5CE: A large parallel-plate capacitor is attached to a battery that has terminal potential (Fig....
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Instructions: Answer the following question based upon your observations in Table 1. (refer to the photo below for the table)

Is the charge (Q) on capacitor directly proportional to potential (V) across its plates?

Answer: ______________________________________________________________________________________________________________________________________________________________________________________

Quantity
Observations
Reasons
Charge (Q on caраcitor
Increasing potential charge on
capacitor will increase
9 = ev
Area A, and separation d is
Capacitance =
constant. Therefore, capacitance (C)
is also constant.
Capacitance (C) of capacitor
c =
= constant
on
increasing the potential
The increasing potential of battery
potential across capacitors will also
Potential (V) across capacitor
C = v
increase.
This happens because,
Potential difference = Electric field
* distance
Slowly increasing potential would
result in steady increase in electric
field between the parallel plates.
Electric Field (E) between plates
As the value of distance between
the plates is kept constant so
Electric field is directly
proportional to potential ie
Ec V
According to equation (1), Electric
field is directly proportional to
Applied potential difference and
inversely proportional to distance
between plates. distance remains
constant, so electric field is directly
proportional to Applied potential
difference. When potential increases
slowly, so potential difference also
increases, it means the electric field
between plates also increases.
Direction of motion of electrons
the electric field between plates
through battery
increases
Transcribed Image Text:Quantity Observations Reasons Charge (Q on caраcitor Increasing potential charge on capacitor will increase 9 = ev Area A, and separation d is Capacitance = constant. Therefore, capacitance (C) is also constant. Capacitance (C) of capacitor c = = constant on increasing the potential The increasing potential of battery potential across capacitors will also Potential (V) across capacitor C = v increase. This happens because, Potential difference = Electric field * distance Slowly increasing potential would result in steady increase in electric field between the parallel plates. Electric Field (E) between plates As the value of distance between the plates is kept constant so Electric field is directly proportional to potential ie Ec V According to equation (1), Electric field is directly proportional to Applied potential difference and inversely proportional to distance between plates. distance remains constant, so electric field is directly proportional to Applied potential difference. When potential increases slowly, so potential difference also increases, it means the electric field between plates also increases. Direction of motion of electrons the electric field between plates through battery increases
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