Answer thedo(0.0026L'= L te=) 30 + (-0.0026)s)? (L+= 29.9974and Explain types of errors in menents,1 (L'/L)ME TL = ( 29.9974/30) *500HTL =499.9566657382) Arizontal distance of (500 m) must be lay out with a steel tape, length of the steel tapeder standard conditions is (30 m). Field conditions indicate that standard conditions applyexcept the measured temperature is 50 °C and applied tension 120'N, Determine the correctT= (T-Ts) LxT= (50-2032) A=T= 0.0lounderP= (P-P₂)LAEP-(120-50)3 The standard temperature 20 °C.0.02*21*Coefficient of thermal expansion of steel tape = 11.6x10-6 °C70.005)Standard tension = 50N ∙WC-W² Mass of the tape = 0.05 kg/m2p²-(0.05 janTotal = 0. olo44 +0.005-0.Total (€) =mans.له میشه راه horizontal distance to be laid out, ifModulus of elasticity (E) = 210*106 N/m224 (120) Cross-sectional area of the tape = 0.02 cm²0.0220221.05 +X5 +1·15=3₁3X5=3-3-22X5=111.1-2.4 -1.3567 5-1.3= 55.4fall1₁4.5-2.28 = -0183

Given values: Measured condition: Temperature: Tm = 50 degree C Tension = 120 N Pull: Pm =…

ISL TL = 499.9666667 --20)382) A horizontal distance of (500 m) must be lay out with a steel tape, length of the steel tape olunder standard conditions is (30 m). Field conditions indicate that standard conditions apply except the measured temperature is 50 °C and applied tension 120'N, Determine the correct -b)L E --50)3 The standard temperature20 °C. *21* Coefficient of thermal expansion of steel tape = 11.6x10-6 °C Po Standard tension = 50N 35 الله ميشه له horizontal distance to be laid out, if W L Mass of the tape = 0.05 kg/m P² 5)Modulus of elasticity (E) = 210*106 N/m2 120) Cross-sectional area of the tape = 0.02 cm² 1.05 +X5 +1.15 = 28 X5= 3-3- X5 = 1.1 1.1-2.4 = -1.3 5675-1.3= 55.4 -

ISL TL = 499.9666667 --20)382) A horizontal distance of (500 m) must be lay out with a steel tape, length of the steel tape olunder standard conditions is (30 m). Field conditions indicate that standard conditions apply except the measured temperature is 50 °C and applied tension 120'N, Determine the correct -b)L E --50)3 The standard temperature20 °C. 21 Coefficient of thermal expansion of steel tape = 11.6x10-6 °C Po Standard tension = 50N 35 الله ميشه له horizontal distance to be laid out, if W L Mass of the tape = 0.05 kg/m P² 5)Modulus of elasticity (E) = 210*106 N/m2 120) Cross-sectional area of the tape = 0.02 cm² 1.05 +X5 +1.15 = 28 X5= 3-3- X5 = 1.1 1.1-2.4 = -1.3 5675-1.3= 55.4 -

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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