It is desired to compress the steam from 100 kPa to 5000 kPa isothermally at 500 °C. During this process the thermodynamic properties of steam might change. If steam behaves ideally at its initial conditions, estimate the fugacity of the steam during this compression process.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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It is desired to compress the steam from 100 kPa to 5000 kPa isothermally at 500 °C. During this
process the thermodynamic properties of steam might change. If steam behaves ideally at its initial
conditions, estimate the fugacity of the steam during this compression process.
Transcribed Image Text:It is desired to compress the steam from 100 kPa to 5000 kPa isothermally at 500 °C. During this process the thermodynamic properties of steam might change. If steam behaves ideally at its initial conditions, estimate the fugacity of the steam during this compression process.
Expert Solution
Step 1

Given data: Initial condition: T1=500 °C=773 K , P1=100 kPa

After isothermal compression, final state: T2=T1=773K , P2=5000 kPa

It is also given that the initial condition of steam is ideal. So, fugacity of steam at state 1, f1=P1=100 kPa

From the definition of fugacity: 

Chemical potential = G=G2-G1=RT×lnf2f1  -------------------------------------- (1)

where G = Gibbs Free energy = (H-TS)

R = Universal gas constant = 8.314 J/mol.K

Step 2

For state 1: from steam tables at T1=500 °C=773 K , P1=100 kPaH1=3488.7 kJ/kg , S1=8.8362 kJ/kg.K

So, G1=H1-T1S1=3488.7-773×8.8362

G1=-3341.683 kJ/kg=-3341.683 J/g×18g/mol ------------------ Mwater=18 (g/mol)

G1=-60150.29 J/mol

Now for state 2: from steam tables at : T2=T1=773K , P2=5000 kPaH2=3434.7 kJ/kg , S2=6.9781 kJ/kg.K

So, G2=H2-T2S2=3434.7-773×6.9781

G2=-1959.37 kJ/kg=-1959.37 J/g×18g/mol

G2=-35268.68 J/mol

 

 

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