It is not desirable to use a static array like aux[] in library software since numerous clients may be using the class at once. Give a Merge implementation that doesn't depend on a static array. Do not localise aux[] to combine() Hint: Pass the auxiliary array to the recursive sort() function as an argument.
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It is not desirable to use a static array like aux[] in library software since numerous clients may be using the class at once. Give a Merge implementation that doesn't depend on a static array. Do not localise aux[] to combine()
Hint: Pass the auxiliary array to the recursive sort() function as an argument.
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- Create an insertion sort implementation that sorts arrays of integer values, then compare its performance to the code supplied in the text (which sorts integer values and implicitly uses autoboxing and auto-unboxing to convert).Write java code to do the following: Implement the Quicksort algorithm for both generic lists and generic arrays: Please note you cannot make any additional FUNCTIONS OR METHODS, Everything must be housed within the functions I have provided below: public static <T extends Comparable<T>> void quickSort(final List<T> list, final Comparator<T> comparator) {...} public static <T extends Comparable<T>> void quickSort(final T[] array, final Comparator<T> comparator) {...}What is the best way to implement a stack or a queue so that it can hold an arbitrary number of elements? Select one: a. Using an array, and throwing an exception when the stack or queue is full. b. By creating a bigger array when the stack or queue is full, and copying the elements from the original array. c. Using linked lists to store the collection of elements.
- The implementation of a queue in an array, as given in this chapter, uses the variable count to determine whether the queue is empty or full. You can also use the variable count to return the number of elements in the queue. On the other hand, class linkedQueueType does not use such a variable to keep track of the number of elements in the queue. Redefine the class linkedQueueType by adding the variable count to keep track of the number of elements in the queue. Modify the definitions of the functions addQueue and deleteQueue as necessary. Add the function queueCount to return the number of elements in the queue. Also, write a program to test various operations of the class you defined.Implement a shellsort variant where the increment sequence is stored in an array rather than being computed.Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list def show_ids(M, level=0): k = M.first_node while k is not None: print(" "*2*level, id(k)) if (str(k.value.__class__.__name__) == str(M.__class__.__name__)): show_ids(k.value, level+1) k = k.next W=L2(Node(10, Node(L2(Node(14, Node(15, Node(L2(Node(16, Node(17))))))), Node(20, Node(30)))) )show_ids(W) Develop your solution as follows: - First copy the nodes of the current list (self) - Create a new list with the copied nodes - Loop through the nodes of the new list checking the value field - If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L):…
- Implement the three improvements to mergesort Add a cutoff for small subarrays, test whether the array is already in order, and avoid the copy by switching arguments in the recursive code.I just need the method they are asking for Write a recursive function that takes a start index, array of integers, and a target sum. Your goal is to find whether a subset of the array of integers adds up to the target sum. The start index is initially 0.A target sum of 0 is true for any array. Examples: subsetSum(0, {2, 4, 8}, 10) -> true public boolean subsetSum(int start, int[] nums, int target) { }implement QuickSort of ints that sorts the numbers in the non-decreasing order. Implement the rearrange function using QuickSort ( such that the pivot is set on the extreme left and the rearrangement is carried on on two pointers) using the O(n) time algorithmThe function gets as input an array, and index of the pivot.The function rearranges the array, and returns the index of the pivot after the rearrangement. int rearrange(int* A, int n, int pivot_index); Implement the QuickSort algorithm. - For n<=2 the algorithm just sorts the (small) array (smaller number first). - For n>=3 the algorithm uses the rearrange function with the pivot chosen to be the median of A[0], A[n/2], A[n-1]. void quick_sort(int* A, int n);
- Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list Develop your solution as follows: First copy the nodes of the current list (self) Create a new list with the copied nodes Loop through the nodes of the new list checking the value field If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L): def clone(self): def clone_node(node): return <... YOUR CODE HERE ...> r = <... YOUR CODE HERE...> return r return L4_class(*args,**kwargs)In writing a general-purpose sort method in Java, the sort method needs to compareobjects. There are two ways to give the sort method the code to compare objects,implementing the interfaces Comparable and Comparator respectively. Extend Article class toimplement Comparable interface so that the default sorting of the Articles is by its volumeGiven the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)