Hello, I need help solving(iv and v) with explanations. Please and thank you. 14. Suppose a 3.000 meter-long cylindrical buoy with cross-sectional area A floats in sea water (pw= 1025 kg/m³). The buoy is made of a solid, uniform piece of plastic foam with an averagedensity pb = 702.0 kg/m², but weighted at the bottom to make it stand “upright" in the water.Assume that the sea water is calm, without waves or turbulent currents.(i) Calculate the equilibrium depth D, or how much of the buoy must be under water for it toremain at equilibrium.(ii) The buoy is momentarily displaced downward a small distance y beyond this equilibriumdepth-ergo, it is no longer in equilibrium. Find the relationship between this displacement y and the buoy'ssubsequent acceleration. (Hints: 1. Keep it symbolic for now, and solve algebraically for the acceleration. 2. Thereshould be a lot of stuff that cancels out. 3. Think carefully about the direction of acceleration as compared to thedisplacement, and make sure your signage properly represents that fact. 4. Subsequent parts of this problem aresimply un-doable without a proper answer here.)Based on your answer to (ii), what kind of motion does the buoy exhibit?(a) Inertial motion(b) Simple harmonic motion(c) Projectile motion(d) Centripetal motion(iii)What gave it away(iv) Find the angular frequency and period of the motion.(v) If its initial displacement from the equilibrium depth was 9.58 cm, what is the velocity (speed and direction) of thebuoy exactly 5.55 s after the buoy is released, assuming no losses to drag, viscosity, etc.?

Answered: Image /qna-images/answer/47d1890c-285e-4dc7-ad4f-5bfc81778f89.jpg

(iv) Find the angular frequency and period of the motion. (v) If its initial displacement from the equilibrium depth was 9.58 cm, what is the velocity (speed and direction) of the buoy exactly 5.55 s after the buoy is released, assuming no losses to drag, viscosity, etc.?

(iv) Find the angular frequency and period of the motion. (v) If its initial displacement from the equilibrium depth was 9.58 cm, what is the velocity (speed and direction) of the buoy exactly 5.55 s after the buoy is released, assuming no losses to drag, viscosity, etc.?

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter6: Forced Convection Over Exterior Surfaces

Section: Chapter Questions

Problem 6.34P

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