J (sin 3x)² = sin 3x xp- sin 3x CO = sin 3x xp- sin 3x On simplifying further, y2 (x) = cq sin 3x / cos ec?3xdx = -Co sin 3x= cot 3x 3 - sin 3x cos 3x sin 3x - cos 3x Therefore, y2 (x) = -cos 3x = C cos 3x [C = - II y2 (x) = cos 3x Hence, the second solution of the differential equation is у2 (х) %3D сos 3x.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.4: Values Of The Trigonometric Functions
Problem 38E
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What happens to the arbitrary constant C? Why isn't it included in the final answer?

J (sin 3x)²
= sin 3x
xp-
sin 3x
CO
= sin 3x
xp-
sin 3x
On simplifying further,
y2 (x) = cq sin 3x / cos ec?3xdx
= -Co sin 3x= cot 3x
3
- sin 3x cos 3x
sin 3x
- cos 3x
Therefore,
y2 (x) = -cos 3x
= C cos 3x [C = -
II
y2 (x) = cos 3x
Hence, the second solution of the differential equation is
у2 (х) %3D сos 3x.
Transcribed Image Text:J (sin 3x)² = sin 3x xp- sin 3x CO = sin 3x xp- sin 3x On simplifying further, y2 (x) = cq sin 3x / cos ec?3xdx = -Co sin 3x= cot 3x 3 - sin 3x cos 3x sin 3x - cos 3x Therefore, y2 (x) = -cos 3x = C cos 3x [C = - II y2 (x) = cos 3x Hence, the second solution of the differential equation is у2 (х) %3D сos 3x.
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