John and Fred agree to play a series of tennis games. The first one to win three games is declared the overall winner. Suppose that John is a stronger tennis player than Fred. So, the probability that John wins each game is 0.6, and the outcome of each game is independent of the outcomes of the other games. a) Find the probability that John wins the series in i games, for i = 3, 4, 5. Round your answers to 3 decimal places. Answer: b) Compare the probability that John wins with the probability that he would win if they played a win two-out-of-three series. Round your answers to 3 decimal places. Answer:

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 32E
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John and Fred agree to play a series of tennis games. The first one to win
three games is declared the overall winner. Suppose that John is a
stronger tennis player than Fred. So, the probability that John wins each
game is 0.6, and the outcome of each game is independent of the
outcomes of the other games.
a) Find the probability that John wins the series in i games, for i = 3, 4,
5. Round your answers to 3 decimal places.
Answer:
b) Compare the probability that John wins with the probability that he
would win if they played a win two-out-of-three series. Round your
answers to 3 decimal places.
Answer:
Transcribed Image Text:John and Fred agree to play a series of tennis games. The first one to win three games is declared the overall winner. Suppose that John is a stronger tennis player than Fred. So, the probability that John wins each game is 0.6, and the outcome of each game is independent of the outcomes of the other games. a) Find the probability that John wins the series in i games, for i = 3, 4, 5. Round your answers to 3 decimal places. Answer: b) Compare the probability that John wins with the probability that he would win if they played a win two-out-of-three series. Round your answers to 3 decimal places. Answer:
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