Just explain and solve on how they get the 5.0 x 10^8 that is shown below in the picture:

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 56P: Alarge uniform cylindrical steel rod of density =7.8g/cm3 is 2.0 m long and has a diameter of 5.0...
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Just explain and solve on how they get the 5.0 x 10^8 that is shown below in the picture:

A vertical steel beam in a building supports a load of 6.0 x 104 N. (a) If the length of the
beam is 4.0 m and its cross-sectional area is 8.0 x 10-3 m², find the distance the beam is
compressed along its length. (b) What maximum load in newtons could the steel beam
support before failing?
(a) Find the amount of compression in the beam.
ΔL
==Y
A
F
Lo
FLo
AL =
YA
(6.0 x 104 N)(4.0 m)
(2.0 x 1011 Pa)(8.0 x 10–3 m²)
= 1. 5 x 10-4 m
= 5.0 x 108
8.0 x 10-3m
F = 4. 0 x 106 N
ANAO
Transcribed Image Text:A vertical steel beam in a building supports a load of 6.0 x 104 N. (a) If the length of the beam is 4.0 m and its cross-sectional area is 8.0 x 10-3 m², find the distance the beam is compressed along its length. (b) What maximum load in newtons could the steel beam support before failing? (a) Find the amount of compression in the beam. ΔL ==Y A F Lo FLo AL = YA (6.0 x 104 N)(4.0 m) (2.0 x 1011 Pa)(8.0 x 10–3 m²) = 1. 5 x 10-4 m = 5.0 x 108 8.0 x 10-3m F = 4. 0 x 106 N ANAO
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