k + 6 k+6 Hint: 126 = -te 3 Assume that n is a positive integer. Compute k+1 k3 + 3k² + 2k* k=1

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Q: (Proof) For any integer n, n² + n is even.

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A: See the attachment

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Q: Using mathematical Induction Principle Show n2<n! ; n≥4

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A: Theorem If n be an odd integer the 7n-5 be an even integer.