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KSHawkes Learning Blackboard Le Xelearning.kctcs.edu/webapps/blackboard/content/contentWrapper.jsp?content_id-_31198949_18displayName=Hawkes+Learning&course_id=_493515589_1&na...HHLog outWest Kentuckya Amazon.com: Onlin...Lazy Day Cooking C...t Typing Lessons | Le...CumberlandsEDOL Websites for...Cite This For Me: H...Templates C-Line...PraxisAppsMurray State>Hawkes LearningMAT 71: Foundations of Precalculus (4194_B5Z1)Course ContentLesson: 8.4 Point-Slope FormSave & End PracticeLORIE TRIVETTE2/10Question 3 of 10, Step 1 of 1CorrectIncorrect-3Find the equation for the line that passes through the point (-1, 2), and that is perpendicular to the line with the equation x115х10°10-5-510|Send to InstructorSkipSubmit AnswerTry SimilarTutorO2019 Hawkes Learning7:42 PM84W

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MAT 71: Foundations of Precalculus (4194_B5Z1)
Course Content
Lesson: 8.4 Point-Slope Form
Save & End Practice
LORIE TRIVETTE
2/10
Question 3 of 10, Step 1 of 1
Correct
Incorrect
-3
Find the equation for the line that passes through the point (-1, 2), and that is perpendicular to the line with the equation x
11
5
х
10°
10
-5
-5
10|
Send to Instructor
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Submit Answer
Try Similar
Tutor
O2019 Hawkes Learning
7:42 PM
84
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KS Hawkes Learning Blackboard Le X elearning.kctcs.edu/webapps/blackboard/content/contentWrapper.jsp?content_id-_31198949_18displayName=Hawkes+Learning&course_id=_493515589_1&na... HH Log out West Kentucky a Amazon.com: Onlin... Lazy Day Cooking C... t Typing Lessons | Le... Cumberlands EDOL Websites for... Cite This For Me: H... Templates C-Line... Praxis Apps Murray State > Hawkes Learning MAT 71: Foundations of Precalculus (4194_B5Z1) Course Content Lesson: 8.4 Point-Slope Form Save & End Practice LORIE TRIVETTE 2/10 Question 3 of 10, Step 1 of 1 Correct Incorrect -3 Find the equation for the line that passes through the point (-1, 2), and that is perpendicular to the line with the equation x 11 5 х 10° 10 -5 -5 10| Send to Instructor Skip Submit Answer Try Similar Tutor O2019 Hawkes Learning 7:42 PM 84 W

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Step 1

x = - 3 is a line perpendicular to x- axis, hence a line perpendicular to it would be a line parallel to y axis.

 

Hence, the equation of a straight line parallel...

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