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Lalculate the pH at the halfway point and at the equivalence point for each of the following titrations a. 100.0 ml. of 0.30 M HC;H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH pH at the halfway point pH at the equivalence point %3D b. 100.0 mL of 0.30 M C2H5 NH2 (K = 5.6 x 10 10) titrated by 0.50 M HNO3 %3D pH at the halfway point pH at the equivalence point !3! c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NAOH pH at the halfway point pH at the equivalence point !!

Lalculate the pH at the halfway point and at the equivalence point for each of the following titrations a. 100.0 ml. of 0.30 M HC;H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH pH at the halfway point pH at the equivalence point %3D b. 100.0 mL of 0.30 M C2H5 NH2 (K = 5.6 x 10 10) titrated by 0.50 M HNO3 %3D pH at the halfway point pH at the equivalence point !3! c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NAOH pH at the halfway point pH at the equivalence point !!

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter16: Reactions Between Acids And Bases
Section: Chapter Questions
Problem 16.54QE
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[Review Topics] Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. a 100.0 mL of 0.30M HC,H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH %3D pH at the halfway point= %3D pH at the equivalence point b. 100.0 ml. of 0.30 M C2H; NH, (K, = 5.6 x 10) titrated by 0.50 M HNO, %3D pH at the halfway point = pH at the equivalence point c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NaOH pH at the halfway point= pH at the equivalence point %3D
Transcribed Image Text:[Review Topics] Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. a 100.0 mL of 0.30M HC,H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH %3D pH at the halfway point= %3D pH at the equivalence point b. 100.0 ml. of 0.30 M C2H; NH, (K, = 5.6 x 10) titrated by 0.50 M HNO, %3D pH at the halfway point = pH at the equivalence point c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NaOH pH at the halfway point= pH at the equivalence point %3D
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