LE. 7mm 13mm 7my 12mm 8m 62mm gmm Amm 3mm Smin 10mm 29mm Smm brom 5mm 2mm Fmm al WHAT IS THE DISTANCE OF THE CENTROID FROM THE X-AXIS b) WHAT IS THE DSTAMCE OF THE CEMTROID FROM THE Y- AXIS TA AQN IT TUr V

Q: 500KN A 200mm 100mm C 45° %24

A:

Q: 1. Given the following set of stadia level notes. The instrument used has a stadia interval factor…

A: Given, STA   BACKSIGHT     FORSIGHT         INTERCPETS VERTICAL ANGLES () ROD RDG (RR1)…

Q: PROBLEM 4: Given: b = 300mm, d = 450mm, As' = 2D25mm, d' = 65mm, fc' = 28MPA, and fy = 415MPA. Solve…

A: Given  b=300 mm  d= 450 mm  AS'=2×π4×252= 981.74 mm2 d'=65 mm  fc'=28MPa  fy=415 MPa

Q: CE 13mm. 7my 12mm 8m 62mm amm 3mm Amm Smin 10mm 29mm 5mm bmm 5nm 2mm Fmm g WHAT IS THE DISTANCE OF…

A:

Q: A 1" reading theodolite having a multiplying constant of 100 and an additive constant of 0 was…

A: Taking, S=staff intercept S=3.240-2.853=0.387 d= angle of elevation C=0, K=100

Q: *The R.L, of the point A which is on the floor is 100 m and backsight reading on A is 2.455 m. If…

A:

Q: 2. By using AreamomentMethod, Determinethedeflectionatthefreeendof thebeamshown 180 kN 15 kN/m В D…

A:

Q: 81.32 1 deg. 5632 3 m 1 deg. 2 m 0 kN 0 kN 1 deg. 5 m 1 deg. -43.68 - 4768 1 deg. -8968 -98-68

A: Given- Calculate- Draw the load and moment diagrams for the shear diagram shown

Q: F=90 N 900 mm A 500 mm

A:

Q: 75 N/m 800 N - m B 8 m-

A:

Q: The back sight taken on a B.M. = 500.000m) was 3.415 m. The fore sight taken on the next point (a)…

A: Given, R.L  of benchmark, = 500 m Backsight distance = 3.415 Foresight distance = 2.125 m R.L of…

Q: Problem 6.23 (Ans. 9.93 mm) Wp = 12 kN/m WL 16 kN/m 480 mm 550 mm 4 #22 -6 m- 300 mm 70 mm

A: There are few data Missing in the question. In order to get the given answer 9.93 mm I have the…

Q: Det er m ne the moment of i nert ia of the z- section as shown in t he fi gure about its; a. cent…

A: Consider the figure.

Q: RL of a point 'A' is 100 m and the back sight reading on 'A' is 2.5 m. If the fore sight reading on…

A:

Q: 9KN

A:

Q: Determine EI8 at point Band end of the overhang. Round off your final answer in 2 decimal places. W1…

A: Given  W1= 34KN/m , W2=30 KN/m  X1= 7m , X 2= 6 m  X3= 5m

Q: • The purpose of the adjustment of the standards ngineer's transit is to make the of an a) axis of…

A: The purpose of adjustment of the standards of an engineer's transit is to make the line of sight…

Q: B = 1829m = 508mm 2 E 3 L= D=

A:

Q: 1 deg. 5632 81.32 3 m 1 deg. 2 m O kN YO kN 1 deg 5m 1 deg. -43.68 -4768 1 deg. -89 68

A:

Q: find cg and Ix and ly and Ixy ~ 15cm, 100m isan 40 cm 30cm 200m

A: As per Bartleby's guidelines we are supposed to answer only first three questions. Kindly repost…

Q: エ Fi Fo F2 G F2 L2 A B D Fi : 217.336N F2:449.399N い:2-303 m

A:

Q: 200KN TookN 5m 10m 2I E> CONSTANT =250 GPa I> GO0(10°) mm4 %3D

A:

Q: P/2 d=20mm b=130 mm- P/2 P 200 000 Fig. (1) 000 ²₂ t=25 mm

A: Solution: Given: Rivet: Diameter = 20 mm Diameter of rivet hole = 22 mm b = 130 mm t = 25 mm number…

Q: 50mm 290mm d 230 290mm 50mm 600mm Question 3: 1x = 62 dm² a as? b) Iys? © Ix + lys?

A:

Q: Deter mine the veta tron atpoint of the frame shown in figuve. Takke %3D E= 200x10 mpa / 1=3. x1o…

A:

Q: Calculate the horizontal deflection at E. 15kN E = 200GPa 10kN- IAB = 371 x 106 mm4 IBD = 215 x 106…

A: Given,

Q: 4. It is the difference between the upper stadia hair reading and the lower stadia hair reading a.…

A: 4 . The correct answer is Stadia Interval

Q: -4m El = constant %3D ising E = 70 GPa | = 160 x 106 mm 4 e Integration Metho

A:

Q: Find ¯Ixy for the region shown

A:

Q: Find the radius of a half circle when ý = 5.889mm .A 13m .B 13.89mm .C 13mm .D 13.89m

A:

Q: ISK 30k 9.

A: the above beam is determinate beam and its can be analyze by the given equilibrium equation.…

Q: blä 4 A datum surface in levelling is a vertical surface. level surface. horizontal surface. non of…

A: Datum is any surface in which elevations are referred. The mean sea level always affords a…

Q: The use of orism in reflector help to avoid error in a) O wave length b) C frequency C) O…

A: C) misalignment

Q: 16 KN/m 10 KN/m B E 4m 1.35m 3.15m 1.5m 210mm 180mm 12mm 9mm 180mm 210mm 238 mm 90mm

A:

Q: ByusingAreaMomentMethod, Determinethedeflection 3mtotheleftofrollersupport. 30 kN/m 55 kN + 3 m- 9 m…

A:

Q: The length intercepted on the stadia rod is 3.6 m and the line of sight makes an angle of 3deg15’…

A:

Q: 2 L 13mm 5mm mm 3mm Select one: a. 9.95 b. 10.11 c. 7.52 d. 8.73 6mm

A:

Q: Given the following: b=360mm d=550mm fc'=35MPA fy=420MPA

A: The given is:b=360mmd=550mm fc'=35MPafy=420MPaMu=700kN-m

Q: 94-Det simply supported boam shown in fiy. use Pey = loo sin 4t %3D Pt) %3D m = 50 per unit length C…

A: The deflection of the simply supported beam with udl is to be calculated or standard expression to…

Q: Problem #1 270 kN 180 kN El = constant E=200 GPa B I-420x10° mm Required: 8max 0A OB 3m 4.5m 3m

A:

Q: 600mm2 200mm2 100 kN 300kN 200kN to 0.4m 0.3m 0.3m

A:

Q: termine the cross sectional ORea is 1200mm? ans in CE 700 EN r, 4m C 4m 6 4m G

A:

Q: Q4use the Virtual work methad to find the Virtical and harizontal displacement at joint D. 162 30KN…

A:

Q: 2. Assume the separation for A, B, and C. With the instrument midway between A and B the readings…

A:

Q: A/58 Calculate the moment of inertia of the 300 x 100-mm channel section about the centroidal…

A: Given data: Channel section= 300×100 mm Hand book Ix=6.25×106 mm4

Q: a. saddle b. depression C. summit d. ridge 4. It is the difference between the upper stadia hair…

A: In tacheometry ,  Distance is given by  D = ks+c  S - staff intercept  K = f/i f = focal length. , I…

Q: CE. 43mm Fry 12mm gmR 62mm gmm Amm Smin 10mm 29mm 5mm bom 5nim 2mm Fmm q WHAT iS THE DISTANCE OF THE…

A:

Q: The distance from the sensor to the target in the range direction is known as: Select one: O a.…

A: Draw the figure.

Q: ByusingAreaMomentMethod, Determinethedeflection 3mtotheleftofrollersupport. 30 kN/m 55 kN B A 9 m…

A:

Mechanics of Solids

It is the study of the behavior of solid materials, their characteristics under various circumstances such as variation in external forces, temperature, and other internal factors. It is one of most important study in the field of engineering science, especially chemistry and mechanical engineering. In rigid body, the idealization of the solid body in which deformation is neglected. Deformation is known as the force acting on the solid state system which exerts change in its shape of the body but it continues to be at rest or in a uniform motion but it cannot accelerate. But those solid systems do have elasticity, compressibility and can be bent. This field is very vast since there are wide range of materials around us.