Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3),(aq) + 2 NH,I(aq) PbI, (s) + 2 NH,NO;(aq) What volume of a 0.350 M NH,I solution is required to react with 853 mL of a 0.440 M Pb(NO3)2 solution? volume: mL How many moles of PbI, are formed from this reaction? moles: mol PbI2

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