Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a charged capacitor can be described as the energy associated with the electric field created inside the capacitor. In this problem, you will derive two more formulas for the energy of a charged capacitor; you will then use a parallel-plate capacitor as a vehicle for obtaining the formula for the energy density associated with an electric field. It will be useful to recall the definition of capacitance, C = Q/V, and the formula for the capacitance of a parallel-plate capacitor, C=c04/d, where A is the area of each of the plates and d is the plate separation. As usual, co is the permittivity of free space. ▾ Part A Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor. Express your answer in terms of C and Q. U= Submit ▾ Part C Part B Complete previous part(s) for Part A for Part A undo for Part A redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A to A parallel-plate capacitor is connected to a battery. The energy of the capacitor is Uo. The capacitor remains connected to the battery while the plates are slowly pulled apart until the plate separation doubles. The new energy of the capacitor is U. Find the ratio U/Uo. > View Available Hint(s) Submit - Part D Request Answer %= for Part C for Part Cundo for Part C redo for Part C reset for Part C keyboard shortcuts for Part C help for Part C A parallel-plate capacitor is connected to a battery. The energy of the capacitor is Uo. The capacitor is then disconnected from the battery and the plates are slowly pulled apart until the plate separation doubles. The new energy of the capacitor is U. Find the ratio U/Uo. ▸ View Available Hint(s) for Part D for Part Dundo for Part D redo for Part D reset for Part D keyboard shortcuts for Part D help for Part D

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter25: Capacitance And Dielectrics
Section: Chapter Questions
Problem 49CP: A capacitor is constructed from two square, metallic plates of sides and separation d. Charges +Q...
icon
Related questions
Question
100%
Learning Goal:
To be able to calculate the energy of a charged capacitor and to understand
the concept of energy associated with an electric field.
The energy of a charged capacitor is given by U = QV/2, where Q is the
charge of the capacitor and V is the potential difference across the
capacitor. The energy of a charged capacitor can be described as the
energy associated with the electric field created inside the capacitor.
In this problem, you will derive two more formulas for the energy of a
charged capacitor; you will then use a parallel-plate capacitor as a vehicle
for obtaining the formula for the energy density associated with an electric
field. It will be useful to recall the definition of capacitance, C = Q/V, and
the formula for the capacitance of a parallel-plate capacitor,
C = €0A/d, where A is the area of each of the plates and d is the plate
separation. As usual, eo is the permittiv
of free space.
First, consider a capacitor of capacitance C that has a charge Q and potential difference V.
Part A
Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor.
Express your answer in terms of C and Q.
U =
Submit
Part C
Part B Complete previous part(s)
DE
for Part A for Part A undo for Part A redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A
A parallel-plate capacitor is connected to a battery. The energy of the capacitor is Uo. The capacitor remains connected to the battery while the plates are slowly pulled apart until the
plate separation doubles. The new energy of the capacitor is U. Find the ratio U/Uo.
▸ View Available Hint(s)
Part D
=
Submit
Request Answer
DIS
for Part C for Part Cundo for Part C redo for Part C reset for Part C keyboard shortcuts for Part C help for Part C
Review I
Constants
A parallel-plate capacitor is connected to a battery. The energy of the capacitor is Uo. The capacitor is then disconnected from the battery and the plates are slowly pulled apart until the
plate separation doubles. The new energy of the capacitor is U. Find the ratio U/Uo.
▸ View Available Hint(s)
for Part D for Part Dundo for Part D redo for Part D reset for Part D keyboard shortcuts for Part D help for Part D
Transcribed Image Text:Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a charged capacitor can be described as the energy associated with the electric field created inside the capacitor. In this problem, you will derive two more formulas for the energy of a charged capacitor; you will then use a parallel-plate capacitor as a vehicle for obtaining the formula for the energy density associated with an electric field. It will be useful to recall the definition of capacitance, C = Q/V, and the formula for the capacitance of a parallel-plate capacitor, C = €0A/d, where A is the area of each of the plates and d is the plate separation. As usual, eo is the permittiv of free space. First, consider a capacitor of capacitance C that has a charge Q and potential difference V. Part A Find the energy U of the capacitor in terms of C and Q by using the definition of capacitance and the formula for the energy in a capacitor. Express your answer in terms of C and Q. U = Submit Part C Part B Complete previous part(s) DE for Part A for Part A undo for Part A redo for Part A reset for Part A keyboard shortcuts for Part A help for Part A A parallel-plate capacitor is connected to a battery. The energy of the capacitor is Uo. The capacitor remains connected to the battery while the plates are slowly pulled apart until the plate separation doubles. The new energy of the capacitor is U. Find the ratio U/Uo. ▸ View Available Hint(s) Part D = Submit Request Answer DIS for Part C for Part Cundo for Part C redo for Part C reset for Part C keyboard shortcuts for Part C help for Part C Review I Constants A parallel-plate capacitor is connected to a battery. The energy of the capacitor is Uo. The capacitor is then disconnected from the battery and the plates are slowly pulled apart until the plate separation doubles. The new energy of the capacitor is U. Find the ratio U/Uo. ▸ View Available Hint(s) for Part D for Part Dundo for Part D redo for Part D reset for Part D keyboard shortcuts for Part D help for Part D
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Parallel-plate capacitor
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
University Physics Volume 2
University Physics Volume 2
Physics
ISBN:
9781938168161
Author:
OpenStax
Publisher:
OpenStax
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning