Q4:- The turning moment diagram of one revolution of multi cylinderengine above and below the line of mean resisting torque are given by(-0.32, 4.06, -2.71, 3.29,-3.24, 2.4, -3.74, 2.71, -2.45) cm?. Thefluctuation of speed is limited to 1 1.5 percent of mean speed which is250 rpm. The hoop stress in rim material is limited to 549.2 N/cm2.Neglecting of boss and arm effects , determine the suitable diameterand cross section of flywheel rim if the weight density of rim materialis 0.0706 N/cm. Assume that the width of rim equals four times itsthickness. Hint: the vertical and horizontal scales are 1 cm=588600N.cm and 1 cm= 24° respectively.

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Answered: leglecting of boss and arm effects,…

leglecting of boss and arm effects, determine the suitable diameter nd cross section of flywheel rim if the weight density of rim material

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Free Body Diagram

The system of forces acting on a body tends to either rotate it or make the body undergo motion. In general, when an external agent exerts a force on a body, the body undergoes translational motion and rotational motion. The body has six degrees of freedom under the influence of that force. Here, three degrees of freedom are from the translational motion while the other three are from the rotation motion. However, sometimes the bodies are not allowed to undergo any motion and are fixed, under such conditions the body is said to be constrained.

Question

Q4:- The turning moment diagram of one revolution of multi cylinder
engine above and below the line of mean resisting torque are given by
(-0.32, 4.06, -2.71, 3.29,-3.24, 2.4, -3.74, 2.71, -2.45) cm?. The
fluctuation of speed is limited to 1 1.5 percent of mean speed which is
250 rpm. The hoop stress in rim material is limited to 549.2 N/cm2.
Neglecting of boss and arm effects , determine the suitable diameter
and cross section of flywheel rim if the weight density of rim material
is 0.0706 N/cm. Assume that the width of rim equals four times its
thickness. Hint: the vertical and horizontal scales are 1 cm=588600
N.cm and 1 cm= 24° respectively.

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