Let, {an} = -5, 10, -20, 40, . . . , {bn} = 10, -5, -20, -35, . . . , and {cn} = -2, 1, - 1/2, 1/4 , . . . . . Find the difference between the sum of the first 10 terms of{an} and the sum of the first 10 terms of {bn}.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 35E
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Let, {an} = -5, 10, -20, 40, . . . , {bn} = 10, -5, -20, -35, . . . , and {cn} = -2, 1, - 1/2, 1/4 , . . . . . Find the difference between the sum of the first 10 terms of
{an} and the sum of the first 10 terms of {bn}.

Expert Solution
Step 1

the given sequence are

 {an} = -5, 10, -20, 40, . . . 

{bn} = 10, -5, -20, -35, . . . ,

we have to find the difference between the sum of the first 10 terms of
{an} and the sum of the first 10 terms of {bn}.

Step 2

firstly, we check an is arithmetic or geometric.if an has a common difference then the difference of consecutive terms are same,then it is an arithmetic sequenceif an has a commom ratio then the ratio of consecutive terms are same,then it is an geometric  sequenceNow, for  an find the ratio of the first two terms and then ratio of second and third term.a2a1=10-5=-2    and    a3a2=-20'10=-2the ratio between consecutive term is same i.e. -2 so, an is geometricthe general term of geomertic seriesn is an=a1rn-1here r=-2 (common ratio)a1=-5 ( first term) an=-5-2n-1now we find a10put n=10a10=-5(-2)10-1=-5-29=2560

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