Let E = {a, b}. Let L = {a'ba* | i > 0}. Give a Turing machine (TM) that accepts the language L. Assume ; that, when the TM starts, the head is on a blank symbol, A, and the input string is immediately after that blank symbol on the tape. For example, if the input string were aaabaaa, then the inital tape configuration would be A a aa baaa
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A: Transition No Transition 1 q0a□→q0aaRR 2 q0b□→q0bbR 3 q0□□→q1□□LL 4 q1aa→q1aaLN 5…
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Q: LetΣ ={a, b}. LetL={aibai|i≥0}.Give a Turing machine (TM) that accepts the languageL.Assume (as in…
A: Attached Handwritten Image:
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A: The complete answer is given below .
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A: The complete answer using JFLAP is below:
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Q: Draw a state diagram of a Turing machine (TM) recognizing the fol- lowing language over the alphabet…
A: Check the state diagram of a turing machine below :
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A: Solution: Given,
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A: correct answer is f (last one). below we take all machine and check : Figure 1:
Q: Construct a Turing machine that accepts the language of strings of the form an, where n is a…
A: Here is your answer: First we need to understand with the help of the example. Lets string 1 0 1 1 0…
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A: The answer is
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A: the solution is an given below :
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A: Basic idea: Given a string BBaabaaBB ,where B is blank symbol. First we scan string from left as we…
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A: First we need to understand with the help of the example. Lets string 1 0 1 1 0 1, so w = 1 0 1 and…
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A: Answer a) Transition table:
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- In python, Problem Description:Sheldon and Leonard are physicists who are fixated on the BIG BANG theory. In order to exchange secret insights they have devised a code that encodes UPPERCASE words by shifting their letters forward. Shifting a letter by S positions means to go forward S letters in the alphabet. For example, shifting B by S = 3 positions gives E. However, sometimes this makes us go past Z, the last letter of the alphabet. Whenever this happens we wrap around, treating A as the letter that follows Z. For example, shifting Z by S = 2 positions gives B. Sheldon and Leonard’s code depends on a parameter K and also varies depending on the position of each letter in the word. For the letter at position P, they use the shift value of S = 3P + K. For example, here is how ZOOM is encoded when K = 3. The first letter Z has a shift valueof S = 3 × 1 + 3 = 6; it wraps around and becomes the letter F. The second letter, O, hasS = 3 × 2 + 3 = 9 and becomes X. The last two letters…Correct answer will be upvoted else downvoted. Computer science. Presently Nezzar has a beatmap of n particular focuses A1,A2,… ,An. Nezzar might want to reorder these n focuses so the subsequent beatmap is great. Officially, you are needed to find a change p1,p2,… ,pn of integers from 1 to n, to such an extent that beatmap Ap1,Ap2,… ,Apn is great. In case it is unthinkable, you ought to decide it. Input The primary line contains a solitary integer n (3≤n≤5000). Then, at that point, n lines follow, I-th of them contains two integers xi, yi (−109≤xi,yi≤109) — directions of point Ai. It is ensured that all focuses are unmistakable. Output In case there is no arrangement, print −1. In any case, print n integers, addressing a legitimate change p. In case there are numerous potential replies, you can print any.create a 2 tape Turing machine (use JFLAP) that has on tape 1 the alphabet of a,b,null, on tape 2 the alphabet is 0,1,2,3, null. Tape 1 has initial content of (a+b)*, Tape 2 has initial content of (0+1)* Begin by processing tape 1, if the substring aa is found on tape 1, search tape 2 for the first 00 substring and replace it with 22 if the substring bb is found on tape 1, search tape 2 for the first 11 substring and replace it with 33. If at anytime aa does not have a matching 00 reject if at anytime bb does not have a matching 11 reject else accept after all of tape 1 has been processed.
- A self-avoiding walk in a lattice is a path from one point to another that does not visit the same point twice. Self-avoiding walks have applications in physics, chemistry, and mathematics. They can be used to model chainlike entities such as solvents and polymers. Write a Turtle program that displays a random path that starts from the center and ends ata point on the boundary, as shown in Figure 11.11a, or ends at a dead-end point (i.e., surrounded by four points that have already been visited), as shown in Figure 11.11b. Assume the size of the lattice is 16 * 16.Not pseudocode Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [We are expecting a description of the algorithm, as well as a brief justification of its runtime.]* Assignment: Longest increasing subsequence * * Sequences are a natural source of computational problems. One such * family of problems involves finding subsequences with specified * properties in a given sequence. This exercise asks you to write * a program that, given a sequence * * s(0), s(1), ..., s(n-1) * * of integers as input, finds a ___longest increasing subsequence___ * of the sequence s. * * For example, suppose we are given as input the sequence * * 72, 16, 51, 17, 6, 21, 92, 59, 54, 78, 41, 33, 94, * 85, 83, 56, 2, 46, 57, 44, 73, 6, 47, 47, 0. * * In this sequence, a longest increasing subsequence has length 7. * One example of such an increasing subsequence is * * 16 < 17 < 21 < 54 < 56 < 57 < 73. * * More generally, your program must be such that * given a sequence * * s(0), s(1), ..., s(n-1) * * of integers as input, the program returns a subsequence * * s(i_1), s(i_2), ..., s(i_k) * * that meets all…
- Consider the following predicates defined on N + .E(n) denotes “n is even”, and P (n) denotes “n is prime”. (a) Translate the following into ordinary English.i. ∃n (P (n) ∧ E(n)).ii. ∀n (E(n) ∨ ¬P (n)).iii. ¬∀n (E(n) ∨ P (n)).solve the problem in java:Consider the are n=2 subjects and needed =[4,5]answered questions, to pass.The student has answered =[2,4] questions in the two subjects so far, and can answer another q=1 questions across all subjects combined. The best outcome is to answer an additional question in the second subject on order to pass it, as 2 more answers required to pass the first subject. the max number of subject s that can be passed is 1. the function must return an integer that can represent the max number of subjects that can be passed. public static int maxNumsub(List <Integer> answered, List<Integer> needed, int q){//write code here}Finish code in Mathematica: The representations of HMMs is also the same. Here's what a call to readHMM[] would look like: hmmObject = readHMMFile["Test/humanMalaria.hmm"]= hmmObject$4958, hmmObject["states"]={"M", "H"} hmmObject["initialStateProbs"]={0.5, 0.5} hmmObject["transitionMatrix"]={{0.5, 0.5}, {0.5, 0.5}} hmmObject["alphabet"]={"A", "C", "G", "T"} hmmObject["emissionMatrix"]={{0.3, 0.25}, {0.2, 0.25}, {0.2, 0.25}, {0.3, 0.25}} observationSeq_ is like: {1, 4, 3, 1, 4, 4, 4, 3, 3, 2, 3, 2, 2, 3, 2} You will have two: buildForwardMatrix and buildBackwardMatrix. You will then combine them inside posteriorProbabilities. posteriorDecode calls posteriorProbabilities and uses the result to find the posterior path and output the corresponding state names. Finish the following four functions in Mathematica: buildForwardMatrix[observationSeq_, hmm_] := Module[{numberOfObservations, numberOfStates, forwardMatrix, observationIndex}, (* Put your code for bulding the forward matrix here.…
- Let s be a string of length 2 with characters from {0, 1, 2}, and define statements a, b, c, and d as follows:a = “the first character of s is 0”b = “the first character of s is 1”c = “the second character of s is 1”d = “the second character of s is 2”. Describe the set of all strings for which each of the following is true.Correct answer will be upvoted else Multiple Downvoted. Computer science. inquiry is depicted by a couple of integers li, ri (1≤li<ri≤n). For each question, he needs to decide if there exists a decent aftereffect in s that is equivalent to the substring s[li… ri]. A substring s[i… j] of a string s is the string shaped by characters sisi+1… sj. String an is supposed to be an aftereffect of string b if a can be gotten from b by erasing a few characters without changing the request for the excess characters. An aftereffect is supposed to be acceptable in case it isn't coterminous and has length ≥2. For instance, in the event that s is "1100110", the aftereffects s1s2s4 ("1100110") and s1s5s7 ("1100110") are acceptable, while s1s2s3 ("1100110") isn't acceptable. Would you be able to help Hr0d1y answer each question? Input The primary line of the input contains a solitary integer t (1≤t≤100) — the number of experiments. The portrayal of each experiment is as per the…Write a program in c++ that will allow a user to find the hypotenuse of a right triangle using the Pythagorean Theorem. Note: In triangle ABC, given the figure, side c is the hypotenuse.