Let f (x) = 3ex − 3xThe function f is increasing on the following interval(s):(−∞,∞)(−∞, a)    (−∞, a](a, ∞)[a, ∞)(−∞, a) ∪ (b, ∞)(−∞, a] ∪ [b, ∞)(a, b)[a, b]Nonea =  b =  f is decreasing on the following interval(s):(−∞, ∞)(−∞, c)    (−∞, c](c, ∞)[c, ∞)(−∞, c) ∪ (d, ∞)(−∞, c ] ∪ [d, ∞)(c, d)[c, d]Nonec =  d =

Question
Asked Oct 16, 2019
Let f (x) = 3ex − 3x

The function f is increasing on the following interval(s):



(−∞,∞)
(−∞, a)
    
(−∞, a]
(a, ∞)
[a, ∞)
(−∞, a) ∪ (b, ∞)
(−∞, a] ∪ [b, ∞)
(a, b)
[a, b]
None


a =

 
 


b =

 
 



f is decreasing on the following interval(s):

(−∞, ∞)
(−∞, c)
    
(−∞, c]
(c, ∞)
[c, ∞)
(−∞, c) ∪ (d, ∞)
(−∞, c ] ∪ [d, ∞)
(c, d)
[c, d]
None


c =

 
 


d =

 
 
check_circleExpert Solution
Step 1

If f'(x) > 0 then f(x) will be increasing. 

 For x>0, f(x) wi...

f (x)-Зе*-3х
f (x)-Зе*-3
f'(x)>0
Зе*-3>0
Зе">3
ex>1
x>In
X>0
help_outline

Image Transcriptionclose

f (x)-Зе*-3х f (x)-Зе*-3 f'(x)>0 Зе*-3>0 Зе">3 ex>1 x>In X>0

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Calculus