Question

Asked Oct 16, 2019

Let f (x) = 3e^{x} − 3x

The function f is increasing on the following interval(s):

The function f is increasing on the following interval(s):

(−∞,∞)

(−∞, a)

(−∞, a]

(a, ∞)

[a, ∞)

(−∞, a) ∪ (b, ∞)

(−∞, a] ∪ [b, ∞)

(a, b)

[a, b]

None*a* =

*b* =

*f* is decreasing on the following interval(s):

(−∞, ∞)

(−∞, c)

(−∞, c]

(c, ∞)

[c, ∞)

(−∞, c) ∪ (d, ∞)

(−∞, c ] ∪ [d, ∞)

(c, d)

[c, d]

None*c* =

*d* =

Step 1

If f'(x) > 0 then f(x) will be increasing.

For x>0, f(x) wi...

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