Question

Asked Oct 15, 2019

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Let g(x)=

The function g is increasing on the following interval(s):

square root 49x |

The function g is increasing on the following interval(s):

(−∞, ∞)

(−∞, a)

(−∞, a]

(a, ∞)

[a, ∞)

(−∞, a) ∪ (b, ∞)

(−∞, a] ∪ [b, ∞)

(a, b)

(a, b]

[a, b)

[a, b]

None

a =

b =

b =

*g* is decreasing on the following interval(s):

(−∞, ∞)

(−∞, c)

(−∞, c]

(c, ∞)

[c, ∞)

(−∞, c) ∪ (d, ∞)

(−∞, c] ∪ [d, ∞)

(c, d)

(c, d]

[c, d)

[c, d]

None*c* = *d* =

Step 1

Find the first derivative of the given function as follows.

Step 2

For *g*(*x*) to be increasing *g’*(*x*) has to be...

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