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Let k be a positive real number. Then f(x) = Vk2 -- x2 is continuous on the interval: . (-k, k) b. (-∞0, k) c. (k, +0) d. [k, +∞)

Let k be a positive real number. Then f(x) = Vk2 -- x2 is continuous on the interval: . (-k, k) b. (-∞0, k) c. (k, +0) d. [k, +∞)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 52E
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Let k be a positive real number.
Let k be a positive real number. Then f(x) = Vk² - x² is continuous on the interval: %3D a. (-k, k) b. (-∞, k) c. (k, +0) d. [k, +∞)
Transcribed Image Text:Let k be a positive real number. Then f(x) = Vk² - x² is continuous on the interval: %3D a. (-k, k) b. (-∞, k) c. (k, +0) d. [k, +∞)
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