Please solve Let LThen (01] equals:{(01)" | n> 1}.%3DSelect one or more:O a. [A|O b. 0OC. None of the above.O d. CO e. {we (0, 1}'| w is not a prefix of any word in £}Of ((01)"0| n>0}Let C-{(01)" | n > 1).Let z 0101 and y 010101. Then:Select one:O a r and y are distinguished w.r.t. L by A.Ob. z and y are distinguished w.r.t. C by 01.Oc we cannot make any statement about the distinquishability or indistinguishability of r and y w.r.t Cgiven the information we haveO d. r and y are indistinguishable w.r.t. L.

Defined the given string equals of the language

Answered: Let L = {(01)" | Tn > 1}. Then (01]…

Let L = {(01)" | Tn > 1}. Then (01] equals: %3D Select one or more: O a. [A] O b. 0 OC. None of the above. O d. C O e. {w e {0,1}'| w is not a prefix of any word in £} Of (01)"0 n > 0}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab' >>> longest_unique_substring('abcabcbb')'abc'""" RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements.
def longest_unique_substring(s: str) -> str:"""Given a string <s>, return the longest unique substring that occurs within<s>.A unique substring is a substring within <s> which DOES NOT have anyrepeating characters. As an example, "xd" is unique but "xxd" is not.If there are two equal length unique substrings within <s>, return the onethat starts first (i.e., begins at a smaller index).tips:In order to get your function to run fast, consider using a dictionary tostore the indexes of previously seen characters, from there, you canfollow a set of rules based on each new character you see to determinethe length of the longest unique substring seen so far.>>> longest_unique_substring('aab')'ab'""" RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements.
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Show L = { w | w is an element of {0, 1, 2}* and (the number of 0s in w ≥ the number of 1s in w) and ((the number of 0s + the number of 1s in w) divides the number of 2s in w) } is not context free. You should assume that p is the pumping length and for any string s in L with |s| ≥ p, s can be broken into 5 pieces, s = uvxyz.
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code in python And Vs Xor Shobhit is trying to impress Kriti. Kriti is stuck in a problem and Shobhit wants to solve it to impress her but he can't. So he asks for your help. You are given a positive integer NN, and an array AA of positive integers. The task is to calculate the number of such pairs (i,j)(i,j) where: i<ji<j AiAi &AjAj≥≥AiAiAjAj, where & denotes the bitwise AND operation, and @ denotes the bitwise XOR operation Input Format First-line contains an integer TT denoting the number of test cases. The next line contains a single positive integer NN. The next line contains NN non-negative integers representing the array AA. Output Format Print the number of pairs. Constraints 1≤T≤31≤T≤3 1≤N≤1051≤N≤105 1≤Ai≤1061≤Ai≤106 Time Limit 1 second Example Sample Input 3 5 1 4 3 7 10 3 1 1 1 1 1 Sample Output 1 3 0 Sample Testcase Explanation For the first test case, there is only one pair: (4,7). For the second test case, all pairs are selected. For the Third…
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In §12.2 Lamport's Hash we mentioned the notion of using only 64 bits of the hash. At each stage, 128 bits are computed, 64 bits are thrown away, and the hash of the retained 64 bits is used in the next stage. The purpose of only using 64 bits is so that a human does not need to type as long a string. Assuming the person will still only type 64 bits, does it work if hashn does a hash of all 128 bits of hashn-1, but what the person actually transmits is 64 bits of the result?
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