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Let S be the subspace of R defined by S = {(x1,82, 83, T4, 25) E Rº : #1 = x2, x3 = 204 + x5}. Then the dimension of S is 1. The vectors (1, -1, 2), (2, 3, 1), (3, 2, t) are not basis of R if Suppose U = {(x, y, x + y, z, 2y + z) € F% : x, y, z E F}. Then a subspace W of F such that F = U w is (i): W = {(0,0, a, b, c) e F³ : a, b, c € F} (ii): W = {(0,0, a, 0, b) E F³ : a, b € F} 3. Let T : R R be defined as T (x, Y, z) = (x + y, x – y, x + 2z). Then the basis of range T is 1 2 1 1 1 0 -1 1 0 4 1 Which of the following sets are a basis for the null space of 5.

Let S be the subspace of R defined by S = {(x1,82, 83, T4, 25) E Rº : #1 = x2, x3 = 204 + x5}. Then the dimension of S is 1. The vectors (1, -1, 2), (2, 3, 1), (3, 2, t) are not basis of R if Suppose U = {(x, y, x + y, z, 2y + z) € F% : x, y, z E F}. Then a subspace W of F such that F = U w is (i): W = {(0,0, a, b, c) e F³ : a, b, c € F} (ii): W = {(0,0, a, 0, b) E F³ : a, b € F} 3. Let T : R R be defined as T (x, Y, z) = (x + y, x – y, x + 2z). Then the basis of range T is 1 2 1 1 1 0 -1 1 0 4 1 Which of the following sets are a basis for the null space of 5.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 46E
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Document2 - Microsoft Word (Product Activation Failed) File Home Insert Page Layout References Mailings Review View a ? A Find - A % Cut - 11 * A A Aa 章 T Calibri (Body) AaBbCcDc AaBbCcDc AaBbC AaBbCc AaBI AaBbCcL E Copy ae Replace Paste в IUabe X, х* A- Change Styles 1 Normal I No Spaci.. Heading 1 Heading 2 Title Subtitle A Select - Format Painter Clipboard Font Paragraph Styles Editing 2:1·1•: :M1A: 2:1·3•1: 4:1:5•1 : 6.1:7:1 8. 19.1· 10. 1 11: I · 12. 1 13. I14: 1 15. I 17. 1 18. L Let S be the subspace of R defined by S = {(x1,x2, 13, X4, X5) E R´ : xı = x2, x3 = 2x4 + x5}. Then the dimension of S is 1. The vectors (1, –1, 2), (2, 3, 1), (3, 2, t) are not basis of R3 if 2. {(x, y,x+ y, z, 2y+ 2) € F : x, y, z E F}. Suppose U Then a subspace W of F such that F5 = U eW is (i): W = {(0,0, a, b, c) E F³ : a, b, c e F} (ii): W = {(0,0, a, 0, b) E F5 : a, b E F} 3. Let T: R3 → R³ be defined as T (x, y, z) = (x + y, x – y, x + 2z). Then the basis of range T is 4. 1 2 1 1 0 1 Which of the following sets are a basis for the null space of -11 1 4 1 5. 09:42 PM 2021-10-24 Page: 1 of 1 Words: 4 E EI E E 96% e
Transcribed Image Text:Document2 - Microsoft Word (Product Activation Failed) File Home Insert Page Layout References Mailings Review View a ? A Find - A % Cut - 11 * A A Aa 章 T Calibri (Body) AaBbCcDc AaBbCcDc AaBbC AaBbCc AaBI AaBbCcL E Copy ae Replace Paste в IUabe X, х* A- Change Styles 1 Normal I No Spaci.. Heading 1 Heading 2 Title Subtitle A Select - Format Painter Clipboard Font Paragraph Styles Editing 2:1·1•: :M1A: 2:1·3•1: 4:1:5•1 : 6.1:7:1 8. 19.1· 10. 1 11: I · 12. 1 13. I14: 1 15. I 17. 1 18. L Let S be the subspace of R defined by S = {(x1,x2, 13, X4, X5) E R´ : xı = x2, x3 = 2x4 + x5}. Then the dimension of S is 1. The vectors (1, –1, 2), (2, 3, 1), (3, 2, t) are not basis of R3 if 2. {(x, y,x+ y, z, 2y+ 2) € F : x, y, z E F}. Suppose U Then a subspace W of F such that F5 = U eW is (i): W = {(0,0, a, b, c) E F³ : a, b, c e F} (ii): W = {(0,0, a, 0, b) E F5 : a, b E F} 3. Let T: R3 → R³ be defined as T (x, y, z) = (x + y, x – y, x + 2z). Then the basis of range T is 4. 1 2 1 1 0 1 Which of the following sets are a basis for the null space of -11 1 4 1 5. 09:42 PM 2021-10-24 Page: 1 of 1 Words: 4 E EI E E 96% e
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