One the following is not a Monge patch on the surface (x – y)² + (z – 1)² = 1 x(u, v) – [u + /1= (v – 1)*Je, + uez + ves X(u, v) - [u + v(v - 1)7 – 1]es + uez + ves The above answer The above answer X(u, v) = u+ (v – 1)? – 1e1 + uez + vez X(1, v) = u + V(v – 1)² – 1e1 + uoz + vez O The above answer O The above answer
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- The main point of this exercise is to use Green’s Theorem to deduce a specialcase of the change of variable formula. Let U, V ⊆ R2 be path connected open sets and letG : U → V be one-to-one and C2such that the derivate DG(u) is invertible for all u ∈ U.Let T ⊆ U be a regular region with piecewise smooth boundary, and let S = G(T). Solve all of them plzThe main point of this exercise is to use Green’s Theorem to deduce a specialcase of the change of variable formula. Let U, V ⊆ R2 be path connected open sets and letG : U → V be one-to-one and C2such that the derivate DG(u) is invertible for all u ∈ U.Let T ⊆ U be a regular region with piecewise smooth boundary, and let S = G(T). Answer CLet, w = (xy)/z and x = 2s + t, y = st, z = 2s - t Find (photo attached):
- 3. Find points at which the mapping defined by f(z) = nz+z^n (n E N) is not conformal.28) Bounded by the planes z=x, y=x, x+y=2, and z=0Suppose S is a rectangle in the uv plane with vertices O(0,0), P(delta u, 0), (delta u, delta v), Q(0, delta v). The image of S under the transformation x=g(u,v), y=h(u,v) is a region R in the xy plane. Let O', P' and Q' be the images of O,P,Q, respectively, in the xy plane where O',P',Q' do not all lie on the same line. The coordinates of O' , P', and Q' are (g(0,0),h(0,0)), (g(delta u,0),h(delta u,0)), and (g(0,delta v),h(0,delta v)), respectively. Consider the parallelogram determined by the vectors O'P' and O'Q'. Use the cross product to show that the area of the parallelogram is approximately |J(u,v)|delta(u)delta(v). |J(u,v)| is the jacobian determinant.
- Consider the Cauchy Problem y 0 = a(x) arctan y, y(0) = 1, where a(x) is a continuous function defined on R, such that for every x it holds that |a(x)| ≤ 1. Using the Global Picard–Lindel¨of Theorem, show that there exists a unique solution y defined on R.Let S = {z: 1 =< Re(z) =< 2 & 1 =< Im(z)}. Find the image of transformed region w-plane under bi-linear transformation of f (z) = (z + 1)/(z – 1). (Hint: Note that a semi-line, a line segment or a circular arc can be transformed to a semi-line, line segment or a circular arc under bi- linear transformation. A line is specified completely, if two point on line is determined, while a circle is specified completely if three distinct points are determined.)Show that u = √3+ √2i is algebraic over Q and type its minimal polynomial p(x) = irr(u, Q) below.