Let X be a discrete random variable with the following probability mass function: p(x) = D1 D1 + D2 + D3 + D4 + D5 D2 D1 + D2 + D3+ D4 + D5 D3 D1 D2 + D3+ D4 + D5 D4 D1 + D2 + D3+ D4 + D5 D5 D1+ D2+D3+ D4 + D5 0 x = 1 x=2 x = 3 x=4 x=5 otherwise

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