Let (X1, X2, X3) be the random outcome of tossing a fair six-faced die three times, and let (Y(1), Y(2), Y(3) be the order statistics from (Х, Х2, Хз). We have Y(1) —D min (X1, Xz, Хз), Y(3) 3D max (X1, Х2, Хз), and Y(1) < Y(2) < Y(3)- Find Pr (Y(1) = 3).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 30E
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Let (X1, X2, X3) be the random outcome of tossing a fair six-faced die three times, and let (Y(1), Y(2), Y(3) be the order statistics from
(X1, X2, X3). We have
Y(1) = min (X1, X2, X3),
Y(3)
= max (X1, X2, X3),
and Y(1) < Y(2) < Y(3).
Find Pr (Y(1) = 3).
Transcribed Image Text:Let (X1, X2, X3) be the random outcome of tossing a fair six-faced die three times, and let (Y(1), Y(2), Y(3) be the order statistics from (X1, X2, X3). We have Y(1) = min (X1, X2, X3), Y(3) = max (X1, X2, X3), and Y(1) < Y(2) < Y(3). Find Pr (Y(1) = 3).
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