Let (xn) be a bounded sequence and let s = sup{xn : n e N}. Show that if s ¢ {xn : n E N}, then there is a subsequence of (xn) that converges to s. (Hint: Use Lemma 1.5.1 and use s - 1< s, s- 1/2 < s, s – 1/3 < s, ...)
Let (xn) be a bounded sequence and let s = sup{xn : n e N}. Show that if s ¢ {xn : n E N}, then there is a subsequence of (xn) that converges to s. (Hint: Use Lemma 1.5.1 and use s - 1< s, s- 1/2 < s, s – 1/3 < s, ...)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 72E
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