4zLet y1 = eand y2 = rebe solutions for a homogeneous DE. Then, -is also a solution to the DE.Select one:4zO y= 2ze+3e zO None of these.O y = 2ze-4z+3eO y = 2ze +3e 4zOy= 2ze + 3e4z%3D

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Answered: Let y =e 4z and y = re be solutions for…

Algebra for College Students

10th Edition

ISBN:9781285195780

Author:Jerome E. Kaufmann, Karen L. Schwitters

Publisher:Jerome E. Kaufmann, Karen L. Schwitters

Chapter11: Systems Of Equations

Section11.5: Cramer's Rule

Problem 35PS

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Let y =e 4z and y = re be solutions for a homogeneous DE. Then, is also a solution to the DE. Select one: O y = 2ze A + 3e O None of these. O y= 2zedz + 3e Oy= 2ze 42 + 3e Oy = 2ze + 3e