use bisection method to solve for one real root of sin x - x^3 = 0 on the interval (0.50,1) Absolute error ≤0.0001.
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use bisection method to solve for one real root of sin x - x^3 = 0 on the interval (0.50,1) Absolute error ≤0.0001.
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- Determine dimension x to 3 decimal places.compute the trapezoid and Simpson approximations using 4 subintervals, and compute the error estimate for each. (Finding the maximum values of the second and fourth derivatives can be challenging for some of these: you may use a graphing calculator or computer software to estimate the maximum values.) If you have access to Sage or similar software, approximate each integral to two decimal places.Use Newton's method to find the absolute max of f(x)=xcox along 0<=x<=pi
- Find the critical points, please show the work. f(x)=sin2x+3 on [-pi,pi]Find the slope when x = (√(π/2) / 2) to the graph with the function from the image attachment. Without calculating the integral, but by using a fundamental result.Find the indefinite intergral of: Integral cube root of x^2 - (1/x^2) dx
- I am supposed to use contour integration to solve this integral, but aren't the poles of 2 and 3 on the real axis? Does the contour need to be a semi-circle, or an indented semi-circle with two indents? Can you solve the problem to show me the correct way to do it? Thanks.Use the trapezoidal method to calculate the absolute error of the given integral using 4 subintervals. Find an exact valueFind the exact value of the integral using formulas from geometry.