Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the bending moment(0 ≤ x ≤ 1m) is given by: X 1m Select one: OM (x) = -25 X³ + 300 X-400 (N.m) OM (x) = -25 X³ + 75 X-50 (N.m) OM (x) = -66.7 X³ + 200 X-133.3 (N.m) OM (x) = -8.3 X³ + 100 X-133.3 (N.m) M (x)=-41.7 X³ + 500 X-666.7 (N.m) 150 N/m

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter10: Statically Indeterminate Beams
Section: Chapter Questions
Problem 10.4.34P: The beam AB shown in the figure is simply supported at A and B and supported on a spring of...
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Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the
bending moment(0 ≤ x ≤ 1m) is given by:
X
Select one:
OM (x) = -25 X³ + 300 X-400 (N.m)
1m
OM(x) = -25 X³ +
+75 X-50 (N.m)
OM (x) = -66.7 X³ + 200 X-133.3 (N.m)
O M(x) = -8.3 X³ + 100 X-133.3 (N.m)
O M(x)=-41.7 X³ + 500 X-666.7 (N.m)
150 N/m
Transcribed Image Text:Let's consider a fixed supported beam subjected to a triangular distributed load as shown in the figure below. The equation of the bending moment(0 ≤ x ≤ 1m) is given by: X Select one: OM (x) = -25 X³ + 300 X-400 (N.m) 1m OM(x) = -25 X³ + +75 X-50 (N.m) OM (x) = -66.7 X³ + 200 X-133.3 (N.m) O M(x) = -8.3 X³ + 100 X-133.3 (N.m) O M(x)=-41.7 X³ + 500 X-666.7 (N.m) 150 N/m
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