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Let's graph y - 2x + 3. Recall that in the general slope-intercept equation y=ma + b, the slope is given by m and the y-intercept is given by b. Therefore, the slope of y = 2a + S is 2 and the y-intercept is (0, 3). In order to graph a line, we need two points on that line. We already know that (0, 3) is on the line. Additionally, because the slope of the line is 2, we know that the point (0+1, 3+2) = (1,5) is also on the line. [How do we know that?] -7 -6 -5 -4 -3 -2 Y 54- 4- 3 (0.3) 1+ -2-- |-4-- -6- (1,5) 1 2 3 4 5 6 7

Let's graph y - 2x + 3. Recall that in the general slope-intercept equation y=ma + b, the slope is given by m and the y-intercept is given by b. Therefore, the slope of y = 2a + S is 2 and the y-intercept is (0, 3). In order to graph a line, we need two points on that line. We already know that (0, 3) is on the line. Additionally, because the slope of the line is 2, we know that the point (0+1, 3+2) = (1,5) is also on the line. [How do we know that?] -7 -6 -5 -4 -3 -2 Y 54- 4- 3 (0.3) 1+ -2-- |-4-- -6- (1,5) 1 2 3 4 5 6 7

Intermediate Algebra
Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter11: Conics
Section11.2: Parabolas
Problem 11.30TI: Graph x=y2+2y3 by using properties.
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Let's graph y = 2x + 3. Recall that in the general slope-intercept equation y = m + b, the slope is given by m and the y-intercept is given by b. Therefore, the slope of y = 2x + 3 is 2 and the y-intercept is (0, 3). In order to graph a line, we need two points on that line. We already know that (0, 3) is on the line. Additionally, because the slope of the line is 2, we know that the point (0+1, 3+2) = (1,5) is also on the line. [How do we know that?] -7 -6 -5 -4 -3 -2 Y 4- 3 (0,3) 14 |-4-- -6 (1,5) 1 2 3 4 5 6 7
Transcribed Image Text:Let's graph y = 2x + 3. Recall that in the general slope-intercept equation y = m + b, the slope is given by m and the y-intercept is given by b. Therefore, the slope of y = 2x + 3 is 2 and the y-intercept is (0, 3). In order to graph a line, we need two points on that line. We already know that (0, 3) is on the line. Additionally, because the slope of the line is 2, we know that the point (0+1, 3+2) = (1,5) is also on the line. [How do we know that?] -7 -6 -5 -4 -3 -2 Y 4- 3 (0,3) 14 |-4-- -6 (1,5) 1 2 3 4 5 6 7
I 682997871 ⠀⠀ 12 20 di do to T 6 7-8-9-9-2-8-6- +++ Graph y = 2z - 7.
Transcribed Image Text:I 682997871 ⠀⠀ 12 20 di do to T 6 7-8-9-9-2-8-6- +++ Graph y = 2z - 7.
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