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lim p(v) lim 7. V→1 V→1 = Find p(1). p(1) = p(v) = 7√ 5v² + 4, = 7 lim = ²√ v→ 1 = 7. = 7 = lim v→ 1 5v² +4 5v² +4 5v² + 4 lim v→ 1 5 lim v→ 1 5v² + lim 4 v→ 1 v² = 7√5 (1) + 4 a = 1 +lim 4. v→ 1 by the --Select--- by the ---Select--- by the --Select--- by the ---Select--- by the ---Select--- Thus, by the definition of continuity, p is continuous at a = 1.

lim p(v) lim 7. V→1 V→1 = Find p(1). p(1) = p(v) = 7√ 5v² + 4, = 7 lim = ²√ v→ 1 = 7. = 7 = lim v→ 1 5v² +4 5v² +4 5v² + 4 lim v→ 1 5 lim v→ 1 5v² + lim 4 v→ 1 v² = 7√5 (1) + 4 a = 1 +lim 4. v→ 1 by the --Select--- by the ---Select--- by the --Select--- by the ---Select--- by the ---Select--- Thus, by the definition of continuity, p is continuous at a = 1.

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.5: Graphing Rational Functions
Problem 36PS
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Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a. p(v) = 7√√5v² + 4, lim p(v) lim 7√ 5v² + 4 v→ 1 v→ 1 Find p(1). p(1) = = 7 lim 5v² + 4 v→ 1 -7√ Jim (Sv² + 4) 1 = 7 = 7 a = 1 lim (5v²) + lim 4 v→ 1 V→ 1 5 lim v→ 1 7√5 (1) + 4 v² + lim 4 v→ 1 by the by the ---Select--- by the -Select--- by the --Select--- --Select--- by the --Select--- Thus, by the definition of continuity, p is continuous at a = 1.
Transcribed Image Text:Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a. p(v) = 7√√5v² + 4, lim p(v) lim 7√ 5v² + 4 v→ 1 v→ 1 Find p(1). p(1) = = 7 lim 5v² + 4 v→ 1 -7√ Jim (Sv² + 4) 1 = 7 = 7 a = 1 lim (5v²) + lim 4 v→ 1 V→ 1 5 lim v→ 1 7√5 (1) + 4 v² + lim 4 v→ 1 by the by the ---Select--- by the -Select--- by the --Select--- --Select--- by the --Select--- Thus, by the definition of continuity, p is continuous at a = 1.
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