lim (x)-(.0) tan , -= (A) Does not exist (B) e? (C) 0 (D) ezn (E) e *IN

Q: lim (1-e X-

A: Limiting value of function is the value achieved by function when variable tends to approach certain…

Q: x(cos(x) – 1), x0 sin(x) – x Evaluate: lim-

A: It is given that,  limx→0xcosx-1sinx-x We have to evaluate it.

Q: 1-cos(x) Find lim x-0 2x

A:

Q: lim (In(x))½ ?

A:

Q: lim x→-0 e-x

A: Given: fx=limx→-∞x2e-x

Q: lim (cos(9x)) (+) +0+x

A:

Q: Lim secx -co tx メーマ

A:

Q: lim (cos x)x² 1/x2

A:

Q: 1 5 arctan x/ = ? Use L'Hospital's Rule 4 lim 4 arctan-

A:

Q: cos x ln(x - *) *-+ In (e-e*) 6. lim

A: Topic:- limits calculus

Q: limit as x approaches infinity of (e^x + e^-x)/(e^x - e^-x)

A: Consider the given expression of which limit has to be calculated:

Q: பாதுக lim sec 20 ー1

A:

Q: -lim COS X tanx <-2メ X-8 2 lim 3 x→2 x42x +X-2 A

A:

Q: lim In(r) - 0t

A: Consider the given limit

Q: lim (tan x) cos x x-2 X-

A: This question is based on limits of 0infinty indeterminate form.

Q: lim tan^-1 x divided by x where x is 0 would that be considered undefined?

A:

Q: lim x approaches 0 ................ (x^2 - 1)(2 - cos x)

A: To find the limit of the function as x approaches 0, the function is given as follows: x2-12-cos x

Q: lim   ln(cosx) x → π/2

A:

Q: tan 3x 18. lim 1-cos x 19. lim -0 tanx

A:

Q: sin(x²) x→0 In(cosx) 4. Evaluate lim

A:

Q: x- cosX X- COS X 4. lim,

A: Our Aim is to evaluate the limits given below:-limx→∞x-cos (x)x-(i)

Q: x-sin x' A- Find limx-0 1-cos x.

A: We will apply the L'hospitals rule because the limit is of 0/0 form.

Q: lim (In x) x→0+

A: Given,          limx→0+lnx

Q: 1) lim X-2 2x-4n x(1-cosx) 2) lim х-0 tan(tan?x)

A:

Q: general question on why is the lim of x approaches positive infinity of ekx /xn =infinity and lim of…

A: (A)Firstly, we will plug x=inf we will get inf/inf So, we can use L'hospital rule

Q: l = lim x→0+ In(x)

A: No, its wrong. you are correct limx→∞ln(x)=-∞…

Q: 1-cos (xーT) lim X-n (x-)sin (x-n)

A:

Q: lim (In(x))* ?

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Q: 7- sin-(e*) 2 lim V1 - e2x

A:

Q: lim (In(x))/x

A: We use L'Hospital rule to evaluate the given limit.

Q: (x-sin x) A- Find lim,-0 1-cos X/

A:

Q: lim (4x+cosx) / x ? x---&gt;infinity

A:

Q: Lim e^x +e^-x-x²-2/sin²x-x² when x approaches 0

A: The given limit is, This limit is in 0/0 form, so we can apply L’Hospital's rule,

Q: 1-cos (x-T) lim x→T(x-T)sin (x-π)

A: Given limit, limx→π1-cosx-πx-πsinx-π

Q: lim x -> 0    ln(1+x)-x / 1-cosx   = ?

A: To find lim x -&gt; 0    ln(1+x)-x / 1-cosx   = ?

Q: sinh x Evaluate lim et

A: We have to find limit of given function limx→∞sinhxex We know, sinhx=ex-e-x2 limx→∞sinhxex

Q: +lim x-0 e -x - 8x ex - e x - sin x

A:

Q: lim COS X tanx メー→o <-2メ4リX-8 2lim 3 メ→ 2 xリ_2X メ-2 xツ_2Xメ

A:

Q: Find the limits

A: Given,                     lim(x,y)→(0,ln2)ex-y     And we have to find its limit.

Q: lim cos(x) X- +x 3 TC 2.

A:

Q: Find the limit of sec x as x approaches x lim sec x x->0

A: Topic = Limits

Q: lim =cos メ→! X-1

A:

Q: e* + e-x – x² –- 2 lim sin? x – x2 х — x→0

A: To evaluate: The limit limx→0ex+e-x-x2-2sin2x-x2. Calculation: Use L'Hospital rule to evaluate the…

Q: 73. lim In(cos x)

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Q: 2х а) lim -1-2x (sin 2x)+² - et b) lim -4x - cos x

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Q: tan(x)-sin(x) e. lim x2 tan(x) (In (cos(3x))] f. lim 2x2 tan(x)-x g. lim x0 (sin(x)-x. ex-In(1+x)-1…

A: e) Given data:   The expression for the given limit is limx→0tan(x)-sin(x)x2tan(x).     The given…

Q: lim tan x x- ->

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Q: limx¬1 x(1 – cos-) x→1

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Q: x(cos(x) – 1), sin(x)-x Evaluate: lim

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.