lim x = 9 [Hint: Write |x² – 9|= |x + 3||x – 3|. Show that if |x – 3|< 1, then |x + 3| <7. If you let 8 be the smaller of the numbers 1 and e/7, show that this 8 works.]

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.1: Polynomial Functions Of Degree Greater Than
Problem 57E
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Prove the statement using the ε, ?  definition of a limit. 

lim x = 9 [Hint: Write |x² – 9|= |x + 3||x – 3|.
Show that if |x – 3|< 1, then |x + 3| <7. If you let 8
be the smaller of the numbers 1 and e/7, show that this
8 works.]
Transcribed Image Text:lim x = 9 [Hint: Write |x² – 9|= |x + 3||x – 3|. Show that if |x – 3|< 1, then |x + 3| <7. If you let 8 be the smaller of the numbers 1 and e/7, show that this 8 works.]
Expert Solution
Introduction

As per the question we are given the limit :

limx→3 x2 = 9

And we have to prove it using the ε-δ defination of limits.

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