Linda titrates 60.00 mL of 0.20 M dimethylamine, (CH3)2NH2, with 0.40 M HBr. (CH3)2NH₂ Kb = 5.4 x 10-4 What is the pH of the solution when 15.0 mL of the 0.40 M HBr is added? pH = [?] pH @ 15.00 mL HBr Enter

Chemistry
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Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 88AE: Consider die titration of 50.0 mL of 0.10 M H3A (Ka1 = 5.0 104, Ka2 = 1.0 108, Ka3 = 1.0 1012)...
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Linda titrates 60.00 mL of 0.20 M
dimethylamine, (CH3)2NH2, with
0.40 M HBr.
(CH3)2NH₂ Kb = 5.4 x 10-4
What is the pH of the solution when
15.0 mL of the 0.40 M HBr is added?
pH = [?]
pH @ 15.00 mL HBr
Enter
Transcribed Image Text:Linda titrates 60.00 mL of 0.20 M dimethylamine, (CH3)2NH2, with 0.40 M HBr. (CH3)2NH₂ Kb = 5.4 x 10-4 What is the pH of the solution when 15.0 mL of the 0.40 M HBr is added? pH = [?] pH @ 15.00 mL HBr Enter
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