Question
Asked Nov 1, 2019
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Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. Suppose 38.8 g of hexane is mixed with 59 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Make sure your answer has the correct number of significant digits. 

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Expert Answer

Step 1

The combustion reaction is

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Step 2

The no of moles of

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38.8 no of moles of hexane 84 -0.4619 mol 59 no of moles of oxygen=- 16 3.6875 mol

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Step 3

2 moles of hexane react with 19 moles of oxygen

Ratio=19/2

     &nb...

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0.4619 moles of hexane would require 0.4619x9.5 4.38805 mol therefore oxygen is a limiting reagent one mole of oxygen would require 19 2 -x 3.6875 19 3.6875 moles would require =0.38815 mol

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