listAverage() returns the average number in a list. Which of these functions does this corre O A. function listAverage (1ist){-- var sum for ( var i 0 1< list.length sum sum list i return (sum list.length O . function 1istAverage (list){- -
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- Write a user defined function named as “length_list” function that finds the length of a list of list_node_t nodes. This code should fit with the following code.Partial Code: #include <stdio.h> #include <stdlib.h> /* gives access to malloc */ #define SENT -1 typedef struct list_node_s { int digit; struct list_node_s *restp; } list_node_t; list_node_t *get_list(void); int main(void) { list_node_t *x;int y; x=get_list(); printf("%d\n",x->digit); printf("%d\n",x->restp->digit); printf("%d\n",x->restp->restp->digit); // your length_list function should be called from here printf("Length is: %d",y); } /* * Forms a linked list of an input list of integers * terminated by SENT */ list_node_t * get_list(void) { int data; list_node_t *ansp; [20]scanf("%d", &data); if (data == SENT) { ansp = NULL; } else { ansp = (list_node_t *)malloc(sizeof (list_node_t)); ansp->digit = data; ansp->restp = get_list(); } return (ansp);The following C function takes a single-linked list of integers as a parameter and rearranges the elements of the list. The function is called with the list containing the integers 1, 2, 3, 4, 5, 6, 7 in the given order. What will be the contents of the list after the function completes execution? struct node { int value; struct node *next; }; void rearrange(struct node *list) { struct node *p, * q; int temp; if ((!list) || !list->next) return; p = list; q = list->next; while(q) { temp = p->value; p->value = q->value; q->value = temp; p = q->next; q = p?p->next:0; } } a) 1, 2, 3, 4, 5, 6, 7b) 2, 1, 4, 3, 6, 5, 7c) 1, 3, 2, 5, 4, 7, 6d) 2, 3, 4, 5, 6, 7, 1Define the function (siftNum lst). This function should resolve to all the numbers in the list, lst. For example: (siftNum '(a 8 2 1 m l 90 p 2)) resolves to '(8 2 1 1 90 2).
- hello guys. can you solve the question next? thank you. here is an example that solution should be like in pic. QUESTION: Write a function randomList() that gets three integers as parameters, start, bound and k. This function will create a list of k randomly generated integer numbers between start and bound values (both inclusive), and return the created list. Write a function sqrtList() that gets a list as parameter, print the numbers in the list and their square root. The square roots will be printed with 3 decimal digits. Write Python statements that ask the user to input start, bound and k values, then call the method to perform the calculations and produce the output. At the end print average of numbers by calling the function calculateAverage().Given two lists(List1, List2) of INTs create a third list such that should contain only odd numbers from the first list and even numbers from the second list def mergeList(listOne, listTwo): thirdList = [] #complete the functionOcaml Map functions left Writeafunctionmap_fun_left : (’a -> ’a) list -> ’a list -> ’a list = that is given a list of functions and a list of elements. For each element apply all functions from left to it and keep the result. Return the results as a list. examples map_fun_left [((+)1);( * )2;fun x->x-10] [1;2;3;4];; - : int list = [-6; -4; -2; 0] map_fun_left [(fun x->int_of_char x|> (+) 32 |> char_of_int);(fun x->char_of_int ((int_of_char x) +1))] [’A’;’B’;’C’;’D’];; - : char list = [’b’; ’c’; ’d’; ’e’]
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- Write a function inde which returns the index (start from 1) of the occurrence of a given value. Use helper function. Two functions are enough.inde(1, [1,2,1,1,2,2,1]) → [1,3,4,7] Write a function nele which repeats each element in a list n times. Use helper function. Two functions only.nele([1,2],3) → [1,1,1,2,2,2] Write a function isfact to determine if a positive integer is a factorial number. Do not use any formula such as T(n)=n(n+1)/2. Do it in recursive fashion. Two functions are enough.isfact(120) → trueWrite the following function that sorts and merges two lists into a new sorted list. The new list contains only even numbers. def myMergeEvenList(list1, list2): Enter list1: 10,5,6,7 Enter list2: 12,8,5,0,1 The merged list is: 0,6,8,10,12Q1:Write a function that returns a new list by eliminating theduplicate values in the list. Use the following function header:def eliminateDuplicates(lst):Write a test program that reads in a list of integers, invokes the function,and displays the result. Here is the sample run of the program Enter ten numbers: 2 3 2 1 6 3 4 5 2The distinct numbers are: 1 2 3 6 4 5 Q2:Write a program that reads in your Q1 Pythonsource code file and counts the occurrence of each keyword in the file.Your program should prompt the user to enter the Python source code filename. This is the Q1: code: def eliminateDuplictes(lst):newlist = [] search = set() for i in lst: if i not in search: newlist.append(i) search.add(i) return newlist a=[] n= int(input("Enter the Size of the list:")) for x in range(n):item=input("\nEnter element " + str(x+1) + ":") a.append(item) result = eliminateDuplictes(a) print('\nThe distinct numbers are: ',"%s" % (' '.join(result)))